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Vanyuwa [196]
3 years ago
15

Simplify the expression.

itle="\frac{6}{1+\sqrt{3} }" alt="\frac{6}{1+\sqrt{3} }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

Step-by-step explanation:

Rationalize the denominator by multiplying both denominator & numerator by the conjugate of the denominator.

Conjugate of the denominator  1 + √3 is 1 - √3

\frac{6}{1+\sqrt{3}}=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{(1+\sqrt{3})(1-\sqrt{3})}\\\\=\frac{6(1-\sqrt{3})}{1^{2}-(\sqrt{3})^{2}}\\\\=\frac{6(1-\sqrt{3})}{1-3}\\\\=\frac{6(1-\sqrt{3})}{-2}\\\\=(-3)(1-\sqrt{3})\\\\=-3+3\sqrt{3}

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Ymorist [56]

Answer:

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nataly862011 [7]

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8 0
3 years ago
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Mice21 [21]

Answer:

hey hope this helps

<h3 /><h3>Comparing sides AB and DE </h3>

AB =

\sqrt{ {1}^{2} +  {1}^{2}  }

=  \sqrt{2}

DE

= \sqrt{ {(3 - 5)}^{2} +  {(1 + 1}^{2}  }  \\   = \sqrt{ {( - 2)}^{2}  +  {(2)}^{2} }  \\    = \sqrt{4 + 4}  \\  =  \sqrt{8}  \\   = 2 \sqrt{2}

So DE = 2 × AB

and since the new triangle formed is similar to the original one, their side ratio will be same for all sides.

<u>scale factor</u> = AB/DE

= 2

It's been reflected across the Y-axis

<em>moved thru the translation of 3 units towards the right of positive x- axis </em>

for this let's compare the location of points B and D

For both the y coordinate is same while the x coordinate of B is 0 and that of D is 3

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2 years ago
Enter the value that makes the given equation true. Y+396.23 =574.54
Levart [38]
574.54-396.23= 178.31
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8 0
2 years ago
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