Answer:
Step-by-step explanation:
Hello!
The variable of interest is the readings on thermometers. This variable is normally distributed with mean μ= 0 degrees C and standard deviation σ= 1.00 degrees C.
The objective is to find the readings that are in the top 3.3% of the distribution and the lowest 3.3% of the distribution.
Symbolically:
The lower value P(X≤a)=0.033
Top value P(X≥b)=0.033
(see attachment)
Lower value:
The accumulated probability until "a" is 0.03, since the variable has a normal distribution, to reach the value of temperature that has the lowest 3.3%, you have to work under the standard normal distribution.
First we look the Z value corresponding to 0.033 of probability:
Z= -1.838
Now you reverste the standardization using the formula Z= (a-μ)/δ
a= (Z*δ)+μ
a= (-1.838*1)+0
a= -1.838
Top value:
P(X≥b)=0.033
This value has 0.033 of the distribution above it then 1 - 0.033= 0.967
is below it.
You can rewrite the expression as:
P(X≤b)=0.967
Now you have to look the value of Z that corresponds to 0.967 of accumulated probability:
b= (Z*δ)+μ
b= (1.838*1)+0
b= 1.838
The cutoff values that separates rejected thermometers from the others are -1.838 and 1.838 degrees C.
I hope it helps!
The answer is the first answer is the first option.

Koalagirl133 I think this is the answer I don't know if it is 9,540,000× 10 = 94, 500, 000
A.
F(10)= (10)^2-3(10)-5
F(10)=100-30-5
F(10)=65
B.
F(-3)=(-3)^2-3(-3)-5
F(-3)=9+9-5
F(-3)=13
C.
G(2)= -6(2)+1
G(2)= -12+1
G(2)=-11
D.
G(10)=-6(10)+1
G(10)= -60+1
G(10)= -59
Answer:
5
Step-by-step explanation:
100= 75 + x2
x=5