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rjkz [21]
2 years ago
14

What is the unit rate of 3 accidents in 12 months

Mathematics
2 answers:
Wewaii [24]2 years ago
7 0
Simplify 3 to 12 Divide 3 1 to 4 So the answer is 1 car accident in 4 month ~JZ Hope it helps you out there
adoni [48]2 years ago
5 0
3 times 4 equal 12 or 4 times 3 equal 12 or 12 divided by 3 =4 or 12 divided by 4 = 3 hope this helps
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Here's a graph of a linear function. Write the
Savatey [412]

there is no visible graph

Step-by-step explanation:

4 0
3 years ago
20 points, please help
Damm [24]

Answer:

The answer to your question is:    83 + 6\sqrt{35}

Step-by-step explanation:

This is a square of a binomial.

                                  (2\sqrt{5} + 3\sqrt{7} )^{2}

1.- Square of the first term

                               ( 2\sqrt{5} )^{2} = 4(5) = 20

2.- Twice the product of the two terms

               (2)(2\sqrt{5} )(3\sqrt{7} ) = 6\sqrt{35}

3.- Square of the second term

                              (3\sqrt{7)})^{2} = 9(7) = 63

4.- Write the solution

                           20 + 6\sqrt{35} + 63

                            83 + 6\sqrt{35}

7 0
3 years ago
8x = 2 write down the value of x
vodomira [7]

x = 0.25

Step-by-step explanation:

8x = 2

x = 2/8

x = 0.25

6 0
2 years ago
Read 2 more answers
If the 16 boys in the classroom are 40% of the class how many students are there in the class
Galina-37 [17]

Answer:

56

Step-by-step explanation:

40+16=56

8 0
3 years ago
Read 2 more answers
Two distinct solid fuel propellants, type A and type B, are being considered for a space program activity. Burning rates of the
Finger [1]

Answer:

C.I. =  (2.297, 11.703)

Step-by-step explanation:

The t-statistic for difference of mean is given by,

t=\frac{\bar{x_{1}}-\bar{x_{2}}}{\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}}}}

Here, \bar{x_{1}} = 84

\bar{x_{2}} = 7

s₁ = 4

n₁ = 12

s₂ = 6

n₂ = 18

Substituting all value in formula,

We get, t = -3.541 at 28 degree of freedom.

Using this formula, we get, t = 1.5342

Therefore, based on the data provided, the 99% confidence interval for the difference between the population means \bar{x_{1}}-\bar{x_{2}} is: 2.297 < \bar{x_{1}}-\bar{x_{2}} < 11.703

which indicates that we are 99% confident that the true difference between population means is contained by the interval (2.297, 11.703)

6 0
3 years ago
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