The measure of the angle ∠PQR is 90 degrees
<h3>How to prove that ∠PQR is 90 degrees?</h3>
The equation of the line PQ is given as:
3x - y - 2 = 0
The coordinates of the QR are given as:
(0, -2) and (6, -4)
Make y the subject in 3x - y - 2 = 0
y = 3x - 2
The slope of the above line is
m1 = 3
Next, we calculate the slope (m2) of points Q and R.
So, we have:
m2 = (y2- y1)/(x2 - x1)
This gives
m2 = (-4 + 2)/(6 - 0)
Evaluate
m2 = -1/3
The slopes of perpendicular lines are opposite reciprocals.
m1 = 3 and m2 = -1/3 are opposite reciprocals.
This means the lines PQ and QR are perpendicular lines.
The angle at the point of perpendicularity is 90 degrees
Hence, the measure of the angle ∠PQR is 90 degrees
Read more about linear equations at:
brainly.com/question/15602982
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Answer:
106°
Step-by-step explanation:
These angles are alternate interior, therefore they are equal to each other.
Answer:
<h2>48</h2>
Step-by-step explanation:
(1)
apple × apple × 2apple = 54
2apple³ = 54 <em>divide both sides by 2</em>
apple³ = 27 → apple = ∛27
apple = 3
(2)
apple + apple × green_apple = 24 <em>substituite apple = 3</em>
3 + 3 × green_apple = 24 <em>subtract 3 from both sides</em>
3 × green_apple = 21 <em>divide both sides by 3</em>
green_apple = 7
(3)
strawberry - bannana - banana = 0 → strawberry = 2banana
(4)
strawberry + banana + cherry = 24 <em>substitute from (3)</em>
2banana + banana + cherry = 24
3banana + cherry = 24
(5)
apple + banana - cherry = -1 <em>substitute apple = 3</em>
3 + banana - cherry = -1 <em>subtr3 from both sides</em>
banana - cherry = -4
Add both sides of (4) and (5)
3banana + cherry = 24
<u>+banana - cherry = -4 </u>
4banana = 20 <em>divide both sides by 4</em>
banana = 5
Substitute it to (4):
3(5) + cherry = 24
15 + cherry = 24 <em>subtract 15 from both sides</em>
cherry = 9
Substitute to the last equation:
3 + 5 × 9 = 3 + 45 = 48
/USED PEMDAS/
<span>If she puts the same amount of confetti in each 5 bags - means that she divides all amount into 5 bags.
So,
4.75 : 5 = 0.95
Answer: each bag should weigh 0.95 pounds.</span>
