1) it must be fulfilled that the denominator is different from zero, then for this expression
x^2 -9 ⇒ x^2-3^2 = (x-3)(x+3)⇒ (x-3)(x+3) = 0 ⇒ x = 3 o x = -3 , the dominium is all numbers reals except 3 and -3
The first box is correct because if drawn on a praph it would show that it has a curve. Also another way to find out if it is nonlinear or linear is because the x-axis is increasing and the y-axis is decreasing. Hope this helps :)
Simplifying
6y + 1 = 21y + 13
Reorder the terms:
1 + 6y = 21y + 13
<span>Reorder the terms:
1 + 6y = 13 + 21y
</span><span>Solving
1 + 6y = 13 + 21y
</span><span>Solving for variable 'y'.
</span><span>Move all terms containing y to the left, all other terms to the right.
</span><span>Add '-21y' to each side of the equation.
1 + 6y + -21y = 13 + 21y + -21y
</span><span>Combine like terms: 6y + -21y = -15y
1 + -15y = 13 + 21y + -21y
</span><span>Combine like terms: 21y + -21y = 0
1 + -15y = 13 + 0
1 + -15y = 13
</span><span>Add '-1' to each side of the equation.
1 + -1 + -15y = 13 + -1
</span>Combine like terms: 1 + -1 = 0
0 + -15y = 13 + -1
-15y = 13 + -1
Combine like terms: 13 + -1 = 12
-15y = 12
Divide each side by '-15'.
y = -0.8
<span>Simplifying
y = -0.8</span>
Answer:
x=9.16
Step-by-step explanation:
Cross multiply
Divide 55 by 6