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3 years ago

Which of the following equations is written in standard form? A. 13= -7y -3x

Mathematics

1 answer:

masya89 [10]3 years ago

5 0

B) 3x+6x=13

I hope this helps

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Help how to solve! 24=3r divided by 4

zhenek [66]

24=3r/4

Multiply both sides by 4

24=(3r)/4

(24)*(4)=(3r/4)*(4)

96=3r

Flip the equation

3r=96

Divide both sides by 3

3r/3=96/3

r=32

Now lets check if the answer is good

24=3(32)/4

24= 96/4

24=24

You see , the answer is good .

I hope that's help ! Let me know .

6 0

2 years ago

If QT is 9 and TP is 8 Find the length of the following: RP RT RS

anyanavicka [17]

Answer:

i. RP = 17

ii. RT = 15

iii. RS = 30

Step-by-step explanation:

Given that; QT = 9 and TP = 8.

From the diagram, join R to P. Thus RP = QP (radius of the circle)

RP = QT + TP

= 9 + 8

RP = 17

Applying Pythagoras theorem to triangle TRP;

RT = $\sqrt{(RP)^{2} - (TP)^{2} }$

= $\sqrt{17^{2} - 8^{2} }$

= $\sqrt{225}$

= 15

∴ RT = 15

But, RT = TS = 15.

So that;

RS = 15 + 15

= 30

RS = 30

Therefore; RP = 17, RT = 15 and RS = 30.

6 0

2 years ago

Two lines intersect at a point, forming ∠1 , ∠2 , ∠3 , and ∠4 .

Ad libitum [116K]

The answer is: [B]: " 60° " .
________________________________________
Because at whatever location, ∠2 and ∠4 are vertical angles;

and all vertical angles have equal measurements.

Given: m∠1 is 120°, and ∠1 is supplementary to ∠2 ;

then m∠1 + m∠2 = 180° .

So, m∠2 = (180 - 120)° = 60° .

As aforementioned:

m∠4 = m∠2 = 60° ; which is: Answer choice: [B]: " 60° " .
___________________________________________________

3 0

3 years ago

Please help! 35 equals 45-n;10,11,12

Alex

35 = 45 -12
Nope

35 = 45 -11
Nope

35 = 45 - 10
Yep!

10 is your answer!

Hope I helped! (Pick my answer as brainliest!)

3 0

2 years ago

Find the domain of the function:

makkiz [27]

Answer: OPTION C.

Step-by-step explanation:

1. The domain of the function given in the problem are all those values for which the function that is in the denomiantor is different from zero, because the division by 0 is not allowed.

2. You can make the denominator equal to zero and solve it, as you can see below:

$x^{3}-2x^{2}+x=0\\x(x^{2}-2x+1)=0\\x(x-1)(x-1)=0\\x=0\\x=1$

3. Therefore, the domain is:

(-∞,0)U(0,1)U(1,∞)

8 0

3 years ago

Read 2 more answers