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stepladder [879]
3 years ago
11

Simplify 2x+x+x+2y x 3y x y

Mathematics
2 answers:
Anarel [89]3 years ago
5 0

Answer:

<h2>4x+6y^3</h2>

Step-by-step explanation:

First you add all the Xs

2x+x+x=4

Then you do

2*3=6

Finally you cube that because there are 3 Ys

olasank [31]3 years ago
3 0

Answer:

3x+6y^3

Step-by-step explanation:

-First you add all the Xs

2x+x+x

-Then you multiply all the Ys

2y * 3y * y

* the Y has a 1 as an exponent by multiplying the Ys the exponents are added making the Y a Y^3

*the numbers are multiplied making it a 6

Together it forms 6y^3

-Ys and Xs cannot be added because they are different values so your answer would be 3x+ 6y^3

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3 ( 5-2(2) 5-4 =1 1×3 =3 ! it's confusing in this format bit the awnser should be 3

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3 years ago
795 divided by 42 does it have a remainder and what’s the answer?
salantis [7]

Answer:

yes it's a decimal 18,9285714286

5 0
3 years ago
Pentagon ABCDE is shown on the coordinate plane below:
goblinko [34]
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4 0
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Read 2 more answers
5 chocolate bars cost $5.75
DerKrebs [107]

Answer:

The answer is $1.85

Step-by-step explanation:

<h3><u>Given</u>;</h3>
  • The cost of 5 chocolate bars = $5.75
  • The cost of 2 chocolate bars and 3 packets of sweets = $7.85
<h3><u>To </u><u>Find</u>;</h3>
  • The cost of one packet of sweets.

Now, we know that the cost of 5 chocolate bars are $5.75.

For 1 chocolate bar

5.75 ÷ 5 = $1.15

Here, we get the price of 1 chocolate bar

So, the cost of 2 chocolate bars and 3 packets of sweets are $7.85.

2 × chocolate bar = 2 × (1.15) = $2.3

Now, we want to find only the cost of one packet of sweets.

So,

7.85 – 2.3 = $5.55

3 packets of sweets cost $5.55

For 1 packets of sweets

5.55 ÷ 3 = $1.85

Thus, The cost of one packet of sweets = $1.85

7 0
3 years ago
Solve each exponential equation by using properties of common logarithms. When necessary, round answers to the nearest hundredth
lisabon 2012 [21]

Answer:

0.08

Step-by-step explanation:

Please use parentheses to indicate which operations must be done first.  I 'm choosing to believe that you meant 7^(3x-1) and 5^(x-1).

Taking the common log of both sides, we get:

(3x-1)log 7 = (x-1)log 5

Then 3x·log 7 - log 7 = x log 5 - log 5

Grouping the x terms:

x(3·log 7 - log 5) = log 7 - log 5.  We combine log 7 and log 5, obtaining log (7/5).

Then x(3·log 7 - log 5) = log (7/5).

Solving for x:

      log (7/5)

x = ---------------------

      3·log 7 - log 5

        0.1461

x   = ------------- = 0.08

         1.0363

This agrees with the 3rd answer choice.

7 0
3 years ago
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