So you would use a frequency table when they are asking for how many times does this come in to the play. For example , let's say there was a play and 2 different characters we're in it the cat came out 3 times and the the dog came out 5 times. Which character came out more times.
Answer:
Step-by-step explanation:
Given
Tile
See attachment for dimension of the floor
Required
Determine the area covered by the carpet
From the attachment, the dimension of the floor is:
Calculate Area
The area of the tiles is:
So, the carpet area is:
To improper number
Take LCM
The answer is kindly 21 (100% correct)
Answer:
first blank is 90/100
second blank is 145/100
Step-by-step explanation:
Answer:
El espesor de un chip es de 0.12mm
Y el diámetro de un átomo de cobre, mide aprox:
0.00000000133 m
Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm
Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm
Primero, escribamos ambos valores en las mismas unidades, sabiendo que:
1m = 1000mm
Podemos reescribir:
0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm
Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm
Esto sera igual al cociente entre 0.12mm y 0.00000133mm, esto es:
N = (0.12mm)/(0.00000133mm) = 90,225.6
Redondeamos al próximo número entero:
N = 90,226
Esa es la cantidad de átomos que se necesitan.
