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4 years ago

What is the area of this triangle in the coordinate plane ASAP

Mathematics

2 answers:

Ira Lisetskai [31]4 years ago

5 0

It’s roughly 24 units2

Leni [432]4 years ago

4 0

Answer:

24 units²

Step-by-step explanation:

The area (A) of a triangle is calculated using the formula

A = $\frac{1}{2}$ bh ( b is the base and h the perpendicular height )

Here b = 8 ( measured along the x- axis) and

h = 6 ( measured along the y- axis )

A = $\frac{1}{2}$ × 8 × 6 = $\frac{1}{2}$ × 48 = 24 units²

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Rearrange to make x the subject

Zolol [24]

Answer
t3/b=x
Step by step explanation
t = bx/3
Take b/3 to the left hand side
= x = 3t/b
Hope it helped !!
Comment below

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3 years ago

Read 2 more answers

Please answer this question(picture included)

zlopas [31]

2xy^2 + 8y => 2y ( xy +4)

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3 years ago

3. Jim bought a new pair of glasses. The lenses had six sides. The lenses were in the shape of a A. hexagon. B. heptagon. C. qua

Vladimir [108]

Best Answer:<span> </span><span>6 sides is a hexagon.

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3 years ago

This table shows the weekly rainfall, in inches, for two cities for ten weeks.

jeka94

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3 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

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3 years ago