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Keith_Richards [23]
2 years ago
12

I’ll make you a brilliant :)

Mathematics
1 answer:
Arlecino [84]2 years ago
4 0
The answer 1 you can right
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Lori has 60% of the book to read. If she has read 120 pages how many pages does she still have to read
maks197457 [2]
Ok, so 120 pages plus the 60% of the book she has left to read will give the total number of pages.

That means that 120 pages is 40% of the book.

Make a proportion

120/40% = x/60%

72 = .4 x

x = 180 pages
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A biologist has been observing a tree's height. This type of tree typically grows by 0.22 feet each month. Fifteen months into t
Lyrx [107]

Data:

x: number of months

y: tree's height

Tipical grow: 0.22

Fifteen months into the observation, the tree was 20.5 feet tall: x=15 y=20.5ft (15,20.5)

In this case the slope (m) or rate of change is the tipical grow.

m=0.22

To find the line's slope-intercep equation you use the slope (m) and the given values of x and y (15 , 20.5) in the next formula to find the y-intercept (b):

\begin{gathered} y=mx+b \\ 20.5=0.22(15)+b \\ 20.5=3.3+b \\ 20.5-3.3=b \\ 17.2=b \end{gathered}

Use the slope(m) and y-intercept (b) to write the equation:

\begin{gathered} y=mx+b \\  \\ y=0.22x+17.2 \end{gathered}A) This line's slope-intercept equation is: y=0.22x+17.2

B) To find the height of the tree after 29 months you substitute in the equation the x for 29 and evaluate to find the y:

\begin{gathered} y=0.22(29)+17.2 \\ y=6.38+17.2 \\  \\ y=23.58 \end{gathered}Then, after 29 months the tree would be 23.58 feet in height

C) In this case as you have the height and need to find the number of moths you substitute the y for 29.96feet and solve the equation for x, as follow:

\begin{gathered} 29.96=0.22x+17.2 \\ 29.96-17.2=0.22x \\ 12.76=0.22x \\ \frac{12.76}{0.22}=x \\  \\ 58=x \end{gathered}Then, after 58 months the tree would be 29.96feet tall
3 0
1 year ago
What percent of $200 is $40?
forsale [732]
To find the answer to the question we do the equation 40/200*100

Which gets us our answer of 20%
4 0
4 years ago
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the length of a varies string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a
kolbaska11 [484]

Answer: <u><em>512</em></u>

Step-by-step explanation: <u><em>the length of a varies string varies inversely as the frequency of its vibrations. A violin string 10 inches long vibrates at a frequency of 512 cycles per second. Find the frequency of an 8-inch string.​</em></u>

<u><em /></u>

4 0
3 years ago
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