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Morgarella [4.7K]
3 years ago
10

Identify the range of the function

Mathematics
2 answers:
NeX [460]3 years ago
8 0

Answer:

what function

Step-by-step explanation:

Vladimir [108]3 years ago
3 0

the answer is either (2,8) or [2,8}

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Negative 12 - negative 50
seraphim [82]

Answer:

38

Step-by-step explanation:

if you're asking what (-12)-(-50) is the answer is 38 simple method to remember is KCF or KFC same thing just worded differently but it means keep change flip! hope that helped have a great day!!

5 0
2 years ago
Find the product of 2 and 500.
Ilya [14]
The answer is 1,000. 500(2)= 1000
6 0
2 years ago
A record store owner assesses customers entering the store as high school age, college age,
Eva8 [605]

Step-by-step explanation:

(a) P = (0.3)(0.2) + (0.5)(0.6) + (0.2)(0.8)

P = 0.52

(b) (0.5)(0.6) = 0.3

P = 0.3 / 0.52

P = 0.58

3 0
3 years ago
The width of each of five continuous classes in a frequency distribution is 5 and the lower class-limit of the lowest class is 1
Helga [31]

Let x and y be the upper and lower class limit of frequency distribution.

Given, width of the class = 5

⇒ x-y= 5 …

Also, given lower class (y) = 10 On putting y = 10, we get

x – 10= 5 ⇒ x = 15 So, the upper class limit of the lowest class is 15

Hence, the upper class limit of the highest class

=(Number of continuous classes x Class width + Lower class limit of the lowest class)

= 5 x 5+10 = 25+10=35

Hence,’the upper class limit of the highest class is 35.

<em><u>Alternate Method</u></em><em><u>.</u></em>

After finding the upper class limit of the lowest class, the five continuous classes in a frequency distribution with width 5 are 10-15,15-20, 20-25, 25-30 and 30-35.

Thus, the highest class is 30-35..

<h3>Hence, the upper limit of this class is 35.</h3>

<h2>_____________________</h2>

4 0
3 years ago
The Fahrenheit and Celsius scales are related by the equation F=9/5C+32. What temperature is equal to a body temperature of 98.6
____ [38]

\textbf{Substitute\ in\ the\ equation}

\displaystyle 98.6 = \frac{9C}{5} +32

\textbf{Solve\ for\ }C

\displaystyle 66.6 = \frac{9C}{5}

333=9C

\large C=\textbf{37 \textdegree C}

7 0
2 years ago
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