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Morgarella [4.7K]
3 years ago
10

Identify the range of the function

Mathematics
2 answers:
NeX [460]3 years ago
8 0

Answer:

what function

Step-by-step explanation:

Vladimir [108]3 years ago
3 0

the answer is either (2,8) or [2,8}

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Please help only part iv ​
satela [25.4K]

Answer:

f(3) + f(-3) = 10

Step-by-step explanation:

f(3) = 5 - 2(3)

f(-3) = 5 - 2(-3)

f(3) + f(-3) = 5 - 2(3) + 5 - 2(-3)

f(3) + f(-3) = 5 - 6 + 5 +6

f(3) + f(-3) = -1 + 11

f(3) + f(-3) = 10

4 0
3 years ago
Suppose that the ages of members in a large billiards league have a known standard deviation of σ = 12 σ=12sigma, equals, 12 yea
asambeis [7]

Answer:

n\geq 23

Step-by-step explanation:

-For a known standard deviation, the sample size for a desired margin of error is calculated using the formula:

n\geq (\frac{z\sigma}{ME})^2

Where:

  • \sigma is the standard deviation
  • ME is the desired margin of error.

We substitute our given values to calculate the sample size:

n\geq (\frac{z\sigma}{ME})^2\\\\\geq (\frac{1.96\times 12}{5})^2\\\\\geq 22.13\approx23

Hence, the smallest desired sample size is 23

3 0
3 years ago
Line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate
Murljashka [212]

Answer:

B. \frac{25}{64}

Step-by-step explanation:

Please find the attachment.  

We have been given that line segment JM has endpoints with coordinates -2 and 14 on a number line. Points K and L are on segment JM. K has a coordinate of 2 and point L has a coordinate of 8.

The probability that the first point is positioned on JL would be \frac{10}{16} as there are total 10 points on JL as L is at point 8 and J is at point -2 so (8--2=8+2=10). Total number of points on the number line JM is (14--2=14+2=16)  

The probability that second point is not placed on KL would be:

P(\text{The point is not on KL)}=1-\text{probability that point is on KL}

P(\text{The point is not on KL)}=1-\frac{\text{Total points on KL}}{\text{Total points on JM}}

P(\text{The point is not on KL)}=1-\frac{(8-2)}{16}

P(\text{The point is not on KL)}=1-\frac{6}{16}

P(\text{The point is not on KL)}=\frac{16-6}{16}

P(\text{The point is not on KL)}=\frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{10}{16}\times \frac{10}{16}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{5}{8}\times \frac{5}{8}

\text{The probability of getting 1st point on Jl and second point is not on KL}=\frac{25}{64}

Therefore, our desired probability will \frac{25}{64} and option B is the correct choice.

5 0
3 years ago
Which choice explains the correct way to move the decimal to find the quotient in the problem 31.28 ÷ 100? A. 2 places to the ri
aivan3 [116]
C. 2 places to the left

31.28 / 100 = 0,3128
7 0
3 years ago
Read 2 more answers
Which one is it !? How do you do it ? It’s timedddd
wel

heres a key for then

SIN= O/H

COS= A/H

TAN= O/A

CSC= H/O

SEC= H/A

COT= A/O

let me know if u have anymore questions

Answer:

3/5 is ur answer

Step-by-step explanation:

ok so its SIN

SIN is o/h (o= opposite and h= hypotenuse)

so we can look at the picture and it says find the SIN of a

ok so the O would be 3 and the H would be 5

so ur answer would be 3/5

4 0
3 years ago
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