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3 years ago

4) Over the summer gas prices dropped 2%. Which expression shows the new price of

Mathematics

1 answer:

Bess [88]3 years ago

5 0

Answer:

g-0.02g and line your answer options down next time to make them clearer.

Step-by-step explanation:

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dolphi86 [110]

9 2/4

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2 years ago

Find the discriminant and the number of real roots for this equation.

GuDViN [60]

Answer:

Step-by-step explanation:

To find the discriminant you do b^2-4(a)(c), which in this case gives you -28. If your discriminant is less than zero, you will have no real roots.

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3 years ago

in 2001, the population in a town was 12% more than it was in 2000. if the population was 25,160 in 2002, which is 10% more than

blagie [28]

2002=25,160
2001=22,644
2000=19,926.72 (need to round to 19,926)
2001:
25,160/10=2516
25,160-2516

2000:
22,644/10=2,264.4 (10%)
2,264.4/5=452.88 (2%)
2,264.4+452.88=2717.28 (12%)
22,644-2717.28=19.926.72

3 0

3 years ago

A writer earned $7 per hour at her job plus an additional $50 in tips on Friday. She earned more than $99 total. Write and solve

labwork [276]

Answer:

7h + 50 > 99

Step-by-step explanation:

5 0

3 years ago

Which two values of x are roots of the polynomial below?<br> x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

<u>Solution:</u>

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

Hence, the roots of given polynomial are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

6 0

3 years ago