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3 years ago

convert the following logarithmic equation to the equivalent exponential equation. Use the caret (^) to enter exponents. y=ln x

1 answer:

5 0

1. To solve this problem, you need to remember that an exponential function has the following form:

f(x)=a^x

"a" is the base and "x" is the exponent.

2. It is important to know that the logarithmic functions and the exponential functionsare inverse. Then, you have:

y=ln x
 e^y=e^(lnx)
 e^y=x

3. Therefore, the answer is:

x=e^y

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Answer:

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3 years ago

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OMG PLEASE HELP ME ASAP!!!!!!! A local charity sponsors a 5K race to raise money. It receives $55 per race entry and $10,000 in

Dominik [7]

Start with how much profit they are making off each race entry. People pay $55 to race, but $15 of that is expenses so they are only profiting $40 for each entry. Now write one side of the equality. They start with $10,000 in donations, and then have a $40 profit for each race entry. So 10,000+40x. X will represent the unknown number of race entries. What do we want that expression to be equal to? We want 10000+40x>55000. It can also be greater than or equal to, not just greater than. Solve for x. Subtract 10000 from each side resulting in 40x>45000. Divide each side by 40 to solve for x. X>1125. X needs to bbe greater than or equal to 1125. If there are 1125 race entries, the charity will profit exactly $55000, so the lowest number of race entries is 1125

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2 years ago

If a couple were planning to have three children, the sample space summarizing the gender outcomes would be: bbb, bbg, bgb,

marusya05 [52]

Answer:

(a) The sample space is: S = {bb, bg, gb, gg}

(b) The probability that the couple has two girl children is 0.25.

Step-by-step explanation:

A boy child is denoted by, b.

A girl child is denoted by, g.

(a)

A couple has two children.

The sample space for the possible gender of the two children are:

The couple can have two boys, two girls or 1 boy and 1 girl.

So the sample space is:

S = {bb, bg, gb, gg}

(b)

It is provided that the outcomes of the sample space S are equally likely, i.e. each outcome has the same probability of success.

Compute the probability that the couple has two girl children as follows:

P (2 Girls) = Favorable no. of outcomes ÷ Total no. of outcomes

$=\frac{1}{4} \\=0.25$

Thus, the probability that the couple has two girl children is 0.25.

(c)

Compute the probability that the couple has exactly 1 boy and 1 girl child as follows:

P (1 boy & 1 girl) = Favorable no. of outcomes ÷ Total no. of outcomes

$=\frac{2}{4} \\=0.50$

Thus, the probability that the couple has exactly 1 boy and 1 girl child is 0.50.

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2 years ago

Under a dilation, the point (2, 6) is moved to (6, 18).

Sergio039 [100]

Answer:

Step-by-step explanation:

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1 year ago