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3 years ago

Which triangles are congruent by ASA?

Mathematics

2 answers:

ELEN [110]3 years ago

4 0

Triangles are congruent if any pair of corresponding sides and their included angles are equal in bothtriangles. There are five ways to test that two triangles are congruent. This is one of them

kifflom [539]3 years ago

3 0

Answer:

ΔADC ≅ ΔEBC

Step-by-step explanation:

For two Triangles to be congruent by ASA, they have to have two angles which are the same, and their included sides must also be equal(the side between the two angles).

For this scenario:

BC = CD as noted by the single lines through each segment.

∠D in ΔADC =90° and ∠B in ΔEBC = 90°
∠C is common to ΔADC and ΔEBC

Thus,

Both triangles have two angles of the exact same size, with a side length between the two angle of the exact same size.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

What is the area of ABC?

Salsk061 [2.6K]

Answer:

Area of triangle ABC = 10

Option C is correct.

Step-by-step explanation:

We need to find area of triangle ABC

We are given A(2,1) B(4,7) and C(6,3)

The formula used to find $Area \ of \ triangle=\frac{1}{2}base\times height$ ABC is:

In the given triangle base= AC and height = BC

First we need to find the distance between A and C and B and C

The formula used to find distance between AC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=2, y_1=1, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-2)^2+(3-1)^2}\\Distance=\sqrt{(4)^2+(2)^2}\\Distance=\sqrt{16+4}\\Distance=\sqrt{20}$

find distance between BC $Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have $x_1=4, y_1=7, x_2=6, y_2=3$

Putting values and finding distance

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(6-4)^2+(3-7)^2}\\Distance=\sqrt{(2)^2+(4)^2}\\Distance=\sqrt{4+16}\\Distance=\sqrt{20}$

So, We have height = $\sqrt{20}$ and base = $\sqrt{20}$

Finding area of triangle

$Area \ of \ triangle=\frac{1}{2}base\times height\\Area \ of \ triangle=\frac{1}{2}\sqrt{20} \times \sqrt{20} \\Area \ of \ triangle=\frac{1}{2}\times 20\\Area \ of \ triangle=10$

So, Area of triangle ABC = 10

Option C is correct.

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3 years ago

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LuckyWell [14K]

Answer:

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Step-by-step explanation:

20% of 75 is just 15 lol. So i guess 15 Kilograms :)

(brainliest if this is correct for you)

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