The spring .2m far when it is compressed on being supported by a mass of 10kg.
Given: Mass of 30 kg which compresses spring by 0.6m
To find: The compression of the spring when it is supported by a mass of 10 kg
Concept: Compression springs are coiled springs that hold mechanical energy in a compressed state. When these springs are subjected to compressive loads, they compress and shorten, capturing and storing significant potential force.
The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
By using unitary method,
10 is 3 times less than 30.
so, 30/3=10
Also applying the same proportion over the lengths compressed,
we get, 0.6/3=.2
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We have the following system:
y = -2x + 5
3x-4y = 2
Substituting y in equation 2 we have:
3x-4 (-2x + 5) = 2
We clear x:
3x + 8x - 20 = 2
11x = 2 + 20
x = 22/11
x = 2
Then, we substitute x = 2 in equation 1:
y = -2 (2) +5
y = -4 + 5
y = 1
Answer:
The solution to the system of equations is:
x = 2
y = 1
Answer:
11.333333333333 (repeated)
Step-by-step explanation:
1.5 and 10 are like terms, so you need to put them together and keep x on one side by itself. This means that you need to subtract 1.5. The new equation will be .75x = 8.5. Then, you divide by .75. This will then give you the final result, x = 11.3 repeated
So what u would do is 8 times 6 and ur answer is 48 I believe
