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irinina [24]
3 years ago
8

Through: (-3,-5), perp. to y=-1/3x+2

Mathematics
1 answer:
lara [203]3 years ago
7 0
Y = -1/3x + 2.....the slope here is -1/3. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal, flip the slope and change the sign. So the slope is -1/3.....flip it and it becomes - 3/1....change the sign and it becomes 3/1 or just 3. So ur perpendicular line will have a slope of 3.

y = mx + b
slope(m) = 3
(-3,-5)....x = -3 and y = -5
now sub into the formula and find b, the y int
-5 = 3(-3) + b
-5 = -9 + b
-5 + 9 = b
4 = b
so ur perpendicular equation is : y = 3x + 4 <===
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If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y
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We define the probability of a particular event occurring as:
\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have \frac{3}{36} = \frac{1}{12} probability of rolling at least one 5.
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