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3 years ago

How to make this y=21x-7 into standard form

Mathematics

1 answer:

Galina-37 [17]3 years ago

6 0

The standard form is 21x-y-7=0

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Jose sold 102 raffle tickets for his basketball team. If he was given 125 tickets to sell, about what percentage of his tickets

Setler [38]

He sold about <span>80% of his tickets</span>

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3 years ago

Plz someone answer this I need the answer quick

pogonyaev

Answer:

Solution,

$volume = (8 \times 5 \times 5) + (5 \times 6 \times 3) \\ \: \: \: \: \: \: \: \: \: \: \: \: = 200 + 90 \\ \: \: \: \: \: \: \: \: \: = 290 \: {m}^{3}$

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7 0

2 years ago

The midpoint of AB = ([?],[ ])

3241004551 [841]

Answer:

(0,0)

Step-by-step explanation:

$x_{m}=\frac{-2+2}{2}=0\\y_{m}=\frac{-2+2}{2}=0\\$

4 0

3 years ago

Factor completely 3x^2 − x − 4.

ozzi

3x^2 − x − 4

factor

= (3x − 4)(x + 1)

answer

D. (3x − 4)(x + 1)

8 0

2 years ago

Of the Students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of th

soldier1979 [14.2K]

Answer:

$\frac{9}{20}$ students.

Step-by-step explanation:

We have been given that of the students that attended Roosevelt Elementary 6/8 of the school play a sport. Of the students are playing a sport 3/5 of the students are also involved in the drama club.

To find the students are both play a sport and a part of the drama club, we need to find 3/5 part of 6/8 as:

$\text{Students who play a sport and a part of the drama club}=\frac{6}{8}\times \frac{3}{5}$

$\text{Students who play a sport and a part of the drama club}=\frac{3}{4}\times \frac{3}{5}$

$\text{Students who play a sport and a part of the drama club}=\frac{3\times 3}{4\times 5}$

$\text{Students who play a sport and a part of the drama club}=\frac{9}{20}$

Therefore, $\frac{9}{20}$ students play sport and part of the drama club.

5 0

3 years ago