9514 1404 393
Answer:
26.1 ft
Step-by-step explanation:
The height of the kite above your position is the opposite side of a right triangle whose hypotenuse is 50 ft. The relevant trig relation is ...
Sin = Opposite/Hypotenuse
Filling in the known values, we have ...
sin(25°) = height/(50 ft)
height = (50 ft)sin(25°) ≈ 21.1 ft
Added to the height at which you are holding the string, this becomes the total height of the kite.
h = 5 ft + 21.1 ft = 26.1 ft . . . . total height of the kite
Answer:
The one below the square.
Step-by-step explanation:
We know that
the relationship between the 2-dimensional polar and Cartesian coordinates is
r = √(x² + y²)
Θ = tan⁻¹ (y/x)
so
Part a) <span>(2, −2)---------> this point belong to the IV quadrant
</span>r = √(x² + y²)------ r = √(2² + (-2)²)-----> r=√8
Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (2/2)----> 45°
remember that the point belong to the IV quadrant
so
Θ=360-45-----> Θ=315°
the answer part A) is
(r,Θ)=(√8,315°)
Part b) (-1, 3)---------> this point belong to the II quadrant
r = √(x² + y²)------ r = √(-1² + (3)²)-----> r=√10
Θ = tan⁻¹ (y/x)---- Θ = tan⁻¹ (3/1)----> 71.57°
remember that the point belong to the II quadrant
so
Θ=180-71.57-----> Θ=108.43°
the answer part B) is
(r,Θ)=(√10,108.43°)
Answer:
With the initial amount and t the time on hours and t the time in hours. since the half life is 12 hours we can find the parameter of decay like this:
And solving for b we got:
And then we have:
And the model would be given by:
Step-by-step explanation:
Assuming this complete question: "A specific radioactive substance follows a continuous exponential decay model. It has a half-life of 12 hours. At the start of the experiment, 82.6g is present.
"
For this case we can create a model like this one:
With the initial amount and t the time on hours and t the time in hours. since the half life is 12 hours we can find the parameter of decay like this:
And solving for b we got:
And then we have:
And the model would be given by: