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3 years ago

If 24 pencils cost $1.20 then how much does one pencil cost?

Mathematics

2 answers:

maria [59]3 years ago

8 0

Answer:

The cost is $.05 or 5 cents per pencil

Step-by-step explanation:

Take the cost and divide by the number of pencils

1.20 /24

.05

The cost is $.05 or 5 cents per pencil

Masteriza [31]3 years ago

7 0

Answer:

$0.05

Step-by-step explanation:

1.20 divided by 24

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Harrizon [31]

Answer: A. We are 99% confident that the interval from 4.1 to 5.6 actually does contain the true value of mu.

Step-by-step explanation:

The correct interpretation of a 99% confidence interval is that we are 99% confident that the true population mean falls in it.

Given 99% confidence interval : $4.1$

Then, the correct interpretation : We are 99% confident that the interval from 4.1 to 5.6 actually does contain the true value of mu.

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3 years ago

What is the amplitude, period, and phase shift of f(x) = -4 sin(2x + π) - 5?

son4ous [18]

F(x) = -4sin(2x + π) - 5

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A = -π

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Solve for x: dx+fx=8-2dx

Rom4ik [11]

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Step-by-step explanation:

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3 years ago

4 cos²x – 1=0 What is the solution?

andreev551 [17]

Answer:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

Step-by-step explanation:

$4\text{cos}^2(x)-1=0\\4\text{cos}^2(x)=1\\$

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$cos(x)=\pm\frac{1}{2}$

So, when cos(x) is equal to

$\frac{1}{2} \text{ and } -\frac{1}{2}$ ?

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$cos(x)=\frac{1}{2}$

We are talking about x = 60º and x = 300º, Quadrant I and IV, respectively. In radians:

$x=\frac{\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{5\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{\pi}{3}+\pi n, n \in \mathbb{Z}$

For

$cos(x)=-\frac{1}{2}$

We are talking about x = 120º and x = 240º, Quadrant II and III, respectively. In radians:

$x=\frac{2\pi }{3}+2\pi n, n\in \mathbb{Z}$

$\:x=\frac{4\pi }{3}+2\pi n, n \in \mathbb{Z}$

$x=\frac{2\pi }{3}+\pi n, n\in \mathbb{Z}$

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3 years ago