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3 years ago

1.8r + 9 = -5.7r - 6 Show your work and answers.

Mathematics

2 answers:

Inessa [10]3 years ago

8 0

The Answer is

1.08=-20.7>r=-20.7/1.8=
-11.5
The Answer is -11.5

Please star this

ioda3 years ago

4 0

1.8r + 9= -5.7r-6
+5.7r -9 +5.7r -9

7.5r =-15 (divde by 7.5)

r=-2

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James is taking a test to be on a game show to win money. He has to answer 75 questions or more correctly in 3 rounds in order t

Tresset [83]

Answer:

Yes; James got 76 answers correct

Step-by-step explanation:

Round 1: 50 x 0.8 = 40

Round 2: 40 x 0.75 = 30

Round 3: 30 x 0.2 = 6

40 + 30 + 6 = 76

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2 years ago

(b) The area of a rectangular pool is 5488 m\2 If the length of the pool is 98 m, what is its width?

mrs_skeptik [129]

Answer:

Step-by-step explanation:

To find the area of a rectangle we have the foruma A=WxL.

But we already have the area and length so we can plug that in

5488=Wx98

Now its an algebreic expression.

SInce its multiplying we do the opposite, so we divide 98 on both sides.

98/98 crosses itself out so now its 5488/98. Which equals 56. So now our expression is W=56. To fact check we put the numbers 56 and 98 into the formula to see if we get 5488.

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A=5488

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1 year ago

In △ABC point D is the midpoint of AB , point E is the midpoint of BC , and point F is the midpoint of BE . Find area of △ABC, i

xz_007 [3.2K]

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3 years ago

the volume v of a right circular cylinder of radius r and heigh h is V = pi r^2 h 1. how is dV/dt related to dr/dt if h is const

laiz [17]

In general, the volume

$V=\pi r^2h$

has total derivative

$\dfrac{\mathrm dV}{\mathrm dt}=\pi\left(2rh\dfrac{\mathrm dr}{\mathrm dt}+r^2\dfrac{\mathrm dh}{\mathrm dt}\right)$

If the cylinder's height is kept constant, then $\dfrac{\mathrm dh}{\mathrm dt}=0$ and we have

$\dfrac{\mathrm dV}{\mathrm dt}=2\pi rh\dfrac{\mathrm dt}{\mathrm dt}$

which is to say, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ are directly proportional by a factor equivalent to the lateral surface area of the cylinder ( $2\pi r h$ ).

Meanwhile, if the cylinder's radius is kept fixed, then

$\dfrac{\mathrm dV}{\mathrm dt}=\pi r^2\dfrac{\mathrm dh}{\mathrm dt}$

since $\dfrac{\mathrm dr}{\mathrm dt}=0$ . In other words, $\dfrac{\mathrm dV}{\mathrm dt}$ and $\dfrac{\mathrm dh}{\mathrm dt}$ are directly proportional by a factor of the surface area of the cylinder's circular face ( $\pi r^2$ ).

Finally, the general case ( $r$ and $h$ not constant), you can see from the total derivative that $\dfrac{\mathrm dV}{\mathrm dt}$ is affected by both $\dfrac{\mathrm dh}{\mathrm dt}$ and $\dfrac{\mathrm dr}{\mathrm dt}$ in combination.

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2 years ago

6. April works as an emergency medical technician (EMT) and is a photographer. As an EMT she earns $19 per

ElenaW [278]

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3 years ago

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