Problem 2- First we have to insert our numbers into the equation. So we would have l2l-l-7l The ll bars mean to find the absolute value. Absolute value is how many spaces it is between that number and zero. So we can simply this to 2-7=-5
Problem 3- First, we have to insert our numbers into the problem. 2(-2)^3(3) Using PEMDAS or order of operations, we solve the exponent first and simplify from there 2(-8)(3) (-16)(3) (-48) The answer is -48
Problem 4- Again, we have to input the numbers into the equation. (4^2-4(-3))/2 (16-4(-3))/2 (16+12)/2 (28)/2 14 The answer is 14
Problem 5- (3)(-1)-(-1^2) (3)(-1)-(1) -3-1 -4 The answer is -4
Problem 7- l-3-4l- -3^2 l-3-4l- +9 l-7| - +9 7-+9 -2 The answer is -2
Problem 8- 3(-3)^2-4|-3|+6 3(9)-4|-3|+6 27-4|-3|+6 27-12+6 21
