Answer:
Step-by-step explanation:
A(n) = - 9+ (n - 1)(6)
A(3) = -9 + (3-1)*6 = -9 + 2*6 = -9 +12 = 3
A(5) = -9 + 4*6 = -9 + 24 = 15
A(10) = -9 + 9*6 = -9 + 54 = 45
Answer: Third option
Step-by-step explanation:
Remember that:
![\sqrt[n]{x^n}=x](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx)
And the Product of powers property:

The expression is:
![\sqrt[4]{\frac{3}{2x}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cfrac%7B3%7D%7B2x%7D%7D)
To simplify this expression, you need to multiply the denominator and the numerator by
. Then:
![\frac{\sqrt[4]{3}}{\sqrt[4]{2x}}=\frac{\sqrt[4]{3(2^3x^3)}}{\sqrt[4]{2x(2^3x^3)}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3%7D%7D%7B%5Csqrt%5B4%5D%7B2x%7D%7D%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3%282%5E3x%5E3%29%7D%7D%7B%5Csqrt%5B4%5D%7B2x%282%5E3x%5E3%29%7D%7D)
Simplifiying, you get:
![\frac{\sqrt[4]{3(8x^3)}}{\sqrt[4]{2x(2^3x^3)}}=\frac{\sqrt[4]{24x^3}}{\sqrt[4]{2^4x^4}}=\frac{\sqrt[4]{24x^3}}{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B4%5D%7B3%288x%5E3%29%7D%7D%7B%5Csqrt%5B4%5D%7B2x%282%5E3x%5E3%29%7D%7D%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B24x%5E3%7D%7D%7B%5Csqrt%5B4%5D%7B2%5E4x%5E4%7D%7D%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B24x%5E3%7D%7D%7B2x%7D)
You multiply the number of cars(bottom row) by 4 to get the number of tires(top row) so if there are 4 cars then there will be 16 tires. If you think about it, there are 4 tires on a car so you would multiply the number of cars by 4 to get the number of tires
12.29 is the square root of 151 to the nearest hundredth. It is about 12.28820572.