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3 years ago

I REALLY NEED HELP ASAP!!!!!!!!!!!!!!

Mathematics

2 answers:

Alexeev081 [22]3 years ago

7 0

the cubic units/ volume of each 3D shapes are:

cone .1 =157.08

cilindar .2 =502.65

sphere .3 =113.1

Dmitry [639]3 years ago

5 0

Answer:

cone V≈157.08

cylinder V≈502.65

sphere V≈113.1

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What is the solution to the system of equations? Y=-3-2. 5x+2y=15

ivolga24 [154]

Answer:

x=-19

y=55

Step-by-step explanation:

y=-3x-2.

5x+2y=15

substitute y into 5x+2y =15

5x +2 (-3x-2) = 15

distribute

5x -6x-4 = 15

combine like terms

-x-4 =15

add 4 to each side

-x-4+4 = 15+4

-x=19

multiply by -1

x = -19

now lets find y

y= -3x-2

y = -3(-19) -2

y = 57-2

y =55

4 0

3 years ago

The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?

Serhud [2]

Answer:

$b = \sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}}$

Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

$C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi } = \sqrt{\frac{a^{2} + b^{2} }{2} }$

Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$