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Dima020 [189]
3 years ago
12

Roman buys seed packets for the school garden. One packet of radish seeds costs $1.75. One packet of tomato seeds costs $2.50. L

et r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds. Roman spent $62.75 on 32 packets of seeds. How many packets of each type of seeds did Roman buy? Use the table to guess and check.8 tomato and 24 radish 9 tomato and 23 radish 23 tomato and 9 radish 24 tomato and 8 radish
Mathematics
2 answers:
zysi [14]3 years ago
8 0

Answer:

9 tomato and 23 radish

I just took the test

HACTEHA [7]3 years ago
4 0
Answer:

C. t=23,r=9 .

Step-by-step explanation:

Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.

Roman spent $62.75

This implies that,

1.75r+2.5t=62.75...eqn1

Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.

This implies that,

r+t=32...eqn2

Using guess and check means we substitute into the given equation.

A) We substitute t=8,r=24 into both equations.

1.75(8)+2.5(24)=62.75...eqn1

14+60\ne 62.75...eqn1

8+24=32...eqn2

Both equations are not satisfied.

B)

We substitute t=9,r=23 into both equations.

1.75(9)+2.5(23)=62.75...eqn1

15.75+57.5\ne 62.75...eqn1

9+23=32...eqn2

Both equations are not satisfied.

C)

We substitute t=23,r=9 into both equations.

1.75(23)+2.5(9)=62.75...eqn1

40.25+22.5 =62.75...eqn1

23+9=32...eqn2

Both equations are satisfied.

Hence the solution is,

t=23,r=9

D) We substitute t=24,r=8 into both equations.

1.75(24)+2.5(8)=62.75...eqn1

42+20\ne 62.75...eqn1

24+8=32...eqn2

Both equations are not satisfied.
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Step-by-step explanation:

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John has two jobs. For daytime work at a jewelry store he is paid
djyliett [7]

Given Information:

John's mean monthly commission = μ = $10,000

Standard deviation of monthly commission = σ =  $2,000

Answer:

P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%

The probability that John's commission from the jewelry store is  between $9,000 and $11,000 is 38.3%

Step-by-step explanation:

What is Normal Distribution?

We are given a Normal Distribution, which is a continuous probability distribution and is symmetrical around the mean. The shape of this distribution is like a bell curve and most of the data is clustered around the mean. The area under this bell shaped curve represents the probability.  

We want to find out the probability that John's commission from the jewelry store is  between $9,000 and $11,000?

P(9,000 < X < 11,000) = P( \frac{x - \mu}{\sigma} < Z < \frac{x - \mu}{\sigma} )\\\\P(9,000 < X < 11,000) = P( \frac{9,000 - 10,000}{2,000} < Z < \frac{11,000 - 10,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( \frac{-1,000}{2,000} < Z < \frac{1,000}{2,000} )\\\\P(9,000 < X < 11,000) = P( -0.5 < Z < 0.5 )\\\\P(9,000 < X < 11,000) = P( Z < 0.5 ) - P( Z < -0.5 ) \\\\

The z-score corresponding to 0.50 is 0.6915

The z-score corresponding to -0.50 is 0.3085

P(9,000 < X < 11,000) = 0.6915 - 0.3085 \\\\P(9,000 < X < 11,000) = 0.383\\\\P(9,000 < X < 11,000) = 38.3 \%

Therefore, the probability that John's commission from the jewelry store is  between $9,000 and $11,000 is 38.3%

How to use z-table?

Step 1:

In the z-table, find the two-digit number on the left side corresponding to your z-score. (e.g 1.4, 2.2, 0.5 etc.)

Step 2:

Then look up at the top of z-table to find the remaining decimal point in the range of 0.00 to 0.09. (e.g. if you are looking for 0.50 then go for 0.00 column)

Step 3:

Finally, find the corresponding probability from the z-table at the intersection of step 1 and step 2.

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