The table shows how an elevator 500 feet above the ground is descending at a steady rate.

Mathematics

1 answer:

lapo4ka [179]3 years ago

7 0

Answer:

h(t) = -5t + 500

Step-by-step explanation:

At time zero, the elevator is at 500 ft.

At time 5 seconds, the elevator is at 475 ft.

The difference in height is -25 ft.

The elevator traveled -25 ft (25 ft down) in 5 seconds, so it travels at a speed of 5 ft per second. Since it is traveling down, its speed is -5 ft/sec.

For each second of travel, it loses 5 ft of height.

h(t) = -5t + 500

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