Answer:
specific heat
Explanation:
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The % mass/mass concentration of solute in the seawater sample is calculated as below
% mass = mass of the solute /mass of the solvent(sea water) x100
mass of the solute =1.295 g
mass of the solvent(sea water_) = 25.895 g
there the % mass = 1.295/25.895 x100 = 5.001 %
Answer:
1.37 x 
CFU/mL
Explanation:
First, the dilution factor needs to be calculated.
Since four 9 ml dilution blanks were prepared, the dilution factor that yielded 137 colonies is of 
.
Next is to divide the colony forming unit from the dilution by the dilution factor:
137/ = 137 x 
In order to get the CFU/ml, divide the CFU from the dilution by the plated volume (1 mL) from the final dilution tube.
137 x /1 = 1.37 x
Hence, the CFU/ml present in the original <em>E. coli </em> sample is 1.37 x .
cfu/ml = (no. of colonies x dilution factor) / volume of culture plate
The masses of the 2 most
common isotopes of Cl are 35 and 37. Therefore we can formulate 3 possible
masses of Cl2:
<span>
35 + 35 = 70
35 + 37 = 72
37 + 37 = 74
<span>However, Cl 35 is the most common isotope of chlorine of the
two therefore it is the most probable that two Cl 35 atoms will combine, so 70
is the most common among all.
</span></span>
Answer:
p=m/v
m=mass:402g
v=volume:385ml
p=density:?
divide 402 by 385 to get 1.04 the density is 1.04ml
Density (p)= mass (g)/volume (ml)
