VII . A because it contains Br (l), Cl (g) and I (s)
When Lead (II) acetate and Hydrogen sulfide react, they form Lead sulfide and Acetic acid. The reaction is a reduction-oxidation (redox) reaction.
The balanced chemical reaction is this:
Pb(C2H3O2)2 + H2S --> PbS + 2C2H4O2
And the net ionic reaction is this:
Pb2+ + S2- --> PbS
Answer:
See explanation
Explanation:
The molecular mass is the sum of the relative atomic masses of all the atoms in the molecule.
The relative atomic mass of reactants and products are calculated as follows;
Benzoic acid is C7H6O2 hence the molar mass of benzoic acid is ;
7(12) + 6(1) + 2(16) = 84 + 6 + 32 = 122.0 g/mol
Methyl benzoate is C8H8O2
8(12) + 8(1) + 2(16) = 96 + 8 + 32 = 136.0 g/mol
<span>H2SO4 gives 2 moles oh H+ per mole of acid
[H2SO4] = 2M so [H+] = 4M
pH = -log(4) = -.6
Therefore, the pH </span><span>of a 2.0 M H2SO4 solution is -0.6
</span>
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<h3>
Answer:</h3>
1.2 × 10^-11 M
<h3>
Explanation:</h3>
<u>We are given;</u>
Concentration of Hydrogen ions [H⁺] as 0.00083 M
<u>We are required to calculate the concentration of [OH⁻]</u>
We know that;
pH = - log [H⁺]
POH = -log[OH⁻]
Also, pH + pOH = 14
With the concentration of H⁺ we can calculate the pH
pH = -log 0.00083 M
= 3.08
But; pH + pOH = 14
Therefore; pOH = 14 - pH
= 14 - 3.08
= 10.92
But, pOH = -log[OH⁻]
Therefore; [OH] = -Antilog(pOH)
Hence; [OH⁻] = Antilog -10.92
= 1.2 × 10^-11 M
Therefore, [OH⁻] is 1.2 × 10^-11 M
