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Dafna11 [192]
3 years ago
12

Which of the following has a solution set of {x | x = 0}?

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0

Answer:

2

Step-by-step explanation:

uwu

Oliga [24]3 years ago
3 0
Middle option.

<span>(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)

If you work both sides separately you get

</span>(x  ≤ 0) ∩ (x ≥ 0)
<span>
which reduces nicely to 

</span><span>{x | x = 0}</span>
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Please find x and y <br><br>x=y-4 and -2x+3y=6
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Answer:

x=y-4 is x=y-4

y=2+ 2x/2

Step-by-step explanation:

3 0
2 years ago
The variable Z is directly proportional to X. When X is 6, Z has the value 18. What is the value of Z when X=10
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Make a proportion
6/18 = 10/z
Cross multiply
180 = 6z
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3 years ago
Show 2 different solutions to the task.
laila [671]

Answer with Step-by-step explanation:

1. We are given that an expression n^2+n

We have to prove that this expression is always is even for every integer.

There are two cases

1.n is odd integer

2.n is even integer

1.n is an odd positive integer

n square is also odd integer and n is odd .The sum of two odd integers is always even.

When is negative odd integer then n square is positive odd integer and n is negative odd integer.We know that difference of two odd integers is always even integer.Therefore, given expression is always even .

2.When n is even positive integer

Then n square is always positive even integer and n is positive integer .The sum of two even integers is always even.Hence, given expression is always even when n is even positive integer.

When n is negative even integer

n square is always positive even integer and n is even negative integer .The difference of two even integers is always even integer.

Hence, the given expression is always even for every integer.

2.By mathematical induction

Suppose n=1 then n= substituting in the given expression

1+1=2 =Even integer

Hence, it is true for n=1

Suppose it is true for n=k

then k^2+k is even integer

We shall prove that it is true for n=k+1

(k+1)^1+k+1

=k^1+2k+1+k+1

=k^2+k+2k+2

=Even +2(k+1)[/tex] because k^2+k is even

=Sum is even because sum even numbers is also even

Hence, the given expression is always even for every integer n.

3 0
3 years ago
Mathh please help and actually do it
Otrada [13]

Answer:

Parallel

Step-by-step explanation:

they have the same slopes

7 0
2 years ago
Read 2 more answers
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