The point-slope form of the equation for a line can be written as
... y = m(x -h) +k . . . . . . . for a line with slope m through point (h, k)
Your function gives
... f'(h) = m
... f(h) = k
a) The tangent line is then
... y = 5(x -2) +3
b) The normal line will have a slope that is the negative reciprocal of that of the tangent line.
... y = (-1/5)(x -2) +3
_____
You asked for "an equation." That's what is provided above. Each can be rearranged to whatever form you like.
In standard form, the tangent line's equation is 5x -y = 7. The normal line's equation is x +5y = 17.
6a+16
Explanation:
If there's just a variable, there's an understood 1 in front of it. So what that really says is:
7a-1a+16
So, you combine the a's. 7a minus 1a is 6a. Same as 7-1,but you have a variable stuck on the end of it.
6a+16
:^)
Answer:
0,-2 and 2,0
Step-by-step explanation: i graphed it on a chart
The ones with a square in a picture is a 90 degree angle the rest are a 180
