Answer:
FALSE
Step-by-step explanation:
Recall that a function f(x) is of exponential order c, if there exists a constant M such that and a real r such that
Now, take a = 2.5 and b = 2
The functions
are both exponential of order 1, since
but a>b
Answer:
a) ![\bar X = 369.62](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20369.62)
b) ![Median=175](https://tex.z-dn.net/?f=Median%3D175%20)
c) ![Mode =450](https://tex.z-dn.net/?f=%20Mode%20%3D450%20)
With a frequency of 4
d) ![MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5](https://tex.z-dn.net/?f=%20MidR%3D%20%5Cfrac%7BMax%20%2BMin%7D%7B2%7D%3D%20%5Cfrac%7B49%2B3000%7D%7B2%7D%3D%201524.5)
<u>e)</u>![s = 621.76](https://tex.z-dn.net/?f=%20s%20%3D%20621.76)
And we can find the limits without any outliers using two deviations from the mean and we got:
![\bar X+2\sigma = 369.62 +2*621.76 = 1361](https://tex.z-dn.net/?f=%20%5Cbar%20X%2B2%5Csigma%20%3D%20369.62%20%2B2%2A621.76%20%3D%201361)
And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case
Step-by-step explanation:
We have the following data set given:
49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000
Part a
The mean can be calculated with this formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
Replacing we got:
![\bar X = 369.62](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20369.62)
Part b
Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:
![Median=175](https://tex.z-dn.net/?f=Median%3D175%20)
Part c
The mode is the most repeated value in the sample and for this case is:
![Mode =450](https://tex.z-dn.net/?f=%20Mode%20%3D450%20)
With a frequency of 4
Part d
The midrange for this case is defined as:
![MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5](https://tex.z-dn.net/?f=%20MidR%3D%20%5Cfrac%7BMax%20%2BMin%7D%7B2%7D%3D%20%5Cfrac%7B49%2B3000%7D%7B2%7D%3D%201524.5)
Part e
For this case we can calculate the deviation given by:
![s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}](https://tex.z-dn.net/?f=%20s%20%3D%5Csqrt%7B%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn-1%7D%7D)
And replacing we got:
![s = 621.76](https://tex.z-dn.net/?f=%20s%20%3D%20621.76)
And we can find the limits without any outliers using two deviations from the mean and we got:
![\bar X+2\sigma = 369.62 +2*621.76 = 1361](https://tex.z-dn.net/?f=%20%5Cbar%20X%2B2%5Csigma%20%3D%20369.62%20%2B2%2A621.76%20%3D%201361)
And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case
Answer:
12
3 x 4
if its one unit then you just multiply the sides in this case 3 x 4
Answer:
5x^2+120x
Step-by-step explanation:
5x(x+24)
Step 1: Use distributive property to expand the expression. Multiply 5x separately with all the terms inside the bracket.
Step 2: 5x(x) = 5x^2
5x(24) = 120x
Answer: 5x^2+120x
Note: If you need to further solve it, you can factor it.
To Factor;
5x^2+120x
Step 1: Factor out the common: 5x
Step 2: 5x times x = x^2
5x times 24 = 120x
Therefore,
Factored answer: 5x(x+24)
Hope this helps.
Answer:
24.75
Step-by-step explanation:
you want to multiply 4.95×5 and you will get the answer $24.75.