Find Lim f(x) as x->0
for
f(x)=5x-8 ......x<0
f(x)=|-4-x|......x ≥ 0
Clearly
f(0)=|-4-0|=|-4|=4 exists.
The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8
The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4
Since the left and right limits do not both equal f(0), the limit does not exist.
False........................
Sin51=y/12
y=12sin51 units
y≈9.33 units (to nearest hundredth of a unit)
...
tanα=12/5
α=arctan2.4°
α≈67.38° (to nearest hundredth of a degree)
...
tan13=x/24
x=24tan13 units
x≈5.54 units (to nearest hundredth of a unit)
...
sin20=10/x
x=10/sin20 units
x≈29.24 units (to nearest hundredth of a unit)
Answer:
6.9999998e+16
Step-by-step explanation:
You literally just multiply
Answer: 75.4 =
70
+ 5
+ 0.4
Step-by-step explanation:
Hope this helps :)
