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damaskus [11]
3 years ago
11

How do you solve all of these ?

Mathematics
1 answer:
Flura [38]3 years ago
4 0
5)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 5}}\quad ,&{{ -3}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies -1
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-3)=-1(x-5)
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y+3=-x+5\implies y=-x+2

6)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 2}}\quad ,&{{ 1}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 3
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=3(x-2)
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-1=3x-6\implies y=3x-5

7)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 5}}\quad ,&{{ 2}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 0
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=0(x-5)
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-2=0\implies y=2

8)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -2}}\quad ,&{{ 0}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2))
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5

9)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -2}}\quad ,&{{ 0}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2))
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5

10)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{-2}}\quad ,&{{ -2}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-2)=\cfrac{3}{2}(x-(-2))
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x+1
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Someone please help!! :^(
sineoko [7]

Answer:

equation of the table is y=30x+60

60 degrees is what the temperature starts at

to get to 440 degrees he needs 12 minutes and 40 seconds

Step-by-step explanation:

the change in y over change in x is 90/3 which is the slope

slope is 30

if slope is 30 then 30*2+b=120 60+b=120 so b=60 and it is the y intercept

440=30x+60

380=30x

x=12 2/3

x= 12 minutes and 40 seconds

8 0
3 years ago
6.) Convert 7.5 quarts to liters
Serjik [45]

Answer:

7.5 quarts is equal to 7.098 liters

Explanation:

multiply the value in quarts by the conversion factor '0.946352946'. So, 7.5 quarts = 7.5 × 0.946352946 = 7.097647095 liters.

8 0
3 years ago
Simplify and then evaluate the equation<br> when x= 3.<br> -5(x – 5) + 2x = [?]
nadya68 [22]

Answer:

-3x+25

16

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A car is driving at a speed of 40 mi/h. What is the speed of the car in feet per minute? a. 2,400 ft/min b. 211,200 ft/min c. 3,
SCORPION-xisa [38]

Answer:

  3520 ft/min

Step-by-step explanation:

40 mi/h = (40 mi/h)×(5280 ft/mi)×(1 h)/(60 min) = 3520 ft/min

_____

Each conversion factor has a value of 1 (numerator = denominator), so changes the units without changing the speed.

3 0
3 years ago
Guys please last one ok
den301095 [7]
Located at -3 and 5
:)
7 0
3 years ago
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