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damaskus [11]
3 years ago
11

How do you solve all of these ?

Mathematics
1 answer:
Flura [38]3 years ago
4 0
5)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 5}}\quad ,&{{ -3}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies -1
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-3)=-1(x-5)
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y+3=-x+5\implies y=-x+2

6)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 2}}\quad ,&{{ 1}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 3
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=3(x-2)
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-1=3x-6\implies y=3x-5

7)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ 5}}\quad ,&{{ 2}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 0
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=0(x-5)
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y-2=0\implies y=2

8)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -2}}\quad ,&{{ 0}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2))
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5

9)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{ -2}}\quad ,&{{ 0}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2))
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5

10)

\bf \begin{array}{lllll}
&x_1&y_1\\
%   (a,b)
&({{-2}}\quad ,&{{ -2}})\quad 
%   (c,d)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2}
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-2)=\cfrac{3}{2}(x-(-2))
\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
\\\\\\
y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x+1
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Answer:

It is stated in the query that the more attractive the individual, the higher their rank of desirability.

Step-by-step explanation:

This means that we should conclude that the alternative explanation of "higher degree of desire contributes to higher levels of social attractiveness"

In the event of a null hypothesis, we will believe that the degree of attractiveness has no impact on the score of cultural desirability.

(1) Null hypothesis:- The level of attraction does not have an impact on the rating of social desirability.

(2) Alternate hypothesis:- The level of attraction has a positive effect on the ranking of social desirability.

(3) The error of Type I is characterized as the rejection of the true null hypothesis. Therefore, in this case, the type I mistake would be that "the level of attraction has a positive effect on the rating of social desirability while the level of attraction does not have an impact on the rating of social desirability."

(4) The error of type II is characterized as the failure to reject the false null hypothesis. Thus, in this situation, the Type II error would be that "the level of attraction has no impact on the rating of social desirability while the real level of attraction has a positive effect on the rating of social desirability."

(5) We know that the likelihood of having a Form I error is equal to the degree of significance (in percent terms). The significance level, in this case, is 0.05, so the likelihood of making a form I error is 0.05 * 100=5 percent.

Therefore, there is a 5 percent risk of making a Type I mistake.

3 0
3 years ago
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm
Juliette [100K]
<span>A midpoint divides a line or a segment into two equal parts. If D is the midpoint of the segment AC and C is the midpoint of segment DB, what is the length of the segment AB, if AC = 3 cm.</span>

 

If D is the midpoint of AC, then AD=DC

If C is the midpoint of DB, then DC=CB

If AC=3cm. then then DC-3/2=1.5

If DC=1.5 then CB is 1.5 also

AB=AC+CB

AB=3+1.5

AB=4.5

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3 years ago
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pashok25 [27]
<h3>Hello there i hope you are having good day :) Question : Solve the problem by writing an inequality. =  A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work? = So firstly  the each of the shirt cost $12 and the money made for the shirt equals 12$ so the cost per the shirt would be 20 + 8x that lead to needing at least 100$  amount made - cost = profit would equal to 12x - (20-8x) ≥ 100 then you would do 12x-20-8x = 100 then you would also do 4x-20 = 100 then you add 20 and add 20 again that would equal 4x/4x = 120/4  that would finally lead you to the answer that would be x = 30 --->  x ≥ 30</h3><h3>Hopefully this help you.</h3>

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3 years ago
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on the other one all real numbers above 7 are answers since after x is 7 it will be greater the. 5 always.
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Answer:

A.

Step-by-step explanation:

because as X approaches infinity, the negative sign will cause it to go opposite of X.

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