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sergij07 [2.7K]
3 years ago
15

Confused on this a bit. No explanation needed

Mathematics
2 answers:
Softa [21]3 years ago
8 0

Answer:

4 in

Step-by-step explanation:

reasoning: half of a circle is the diameter the radius is half of a diameter

pls give brainliest

btw if you ever need help  talk to me

btw sorry for the explanation

it wouldn't let me explain

Yuri [45]3 years ago
6 0

<em>If half of the circle is 16 inches the radios is 4 because the radios is straight line from the center to the circumference of a circle or sphere.</em>

<em> Answer: 4</em>

<em>Hope this helps~</em>

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Assume that a fair six-sided die is rolled 13 times, and the roll is called a success if the result is in {1,2,3,4}. What is the
Deffense [45]

Answer:

The answer to the question is;

The probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls is \frac{715}{8192}.

Step-by-step explanation:

The probability of success = 1/2 =

probability of failure  = 1/2

Since we have 4 success we then have 9 failures and the given probability can be solved as ₁₃C₄ × 1/2ⁿ×1/2¹³⁻ⁿ

Therefore  we have

₁₃C₄ × 1/2⁴×1/2⁹ =  715/8192

That is the probability that there are exactly 4 successes or exactly 4 failures in the 13 rolls = 715/8192.

5 0
3 years ago
Need help with this math problem
makvit [3.9K]

Answer:

P(x) = x^4 -16x^3 +76x^2 -72x -100

Step-by-step explanation:

The two roots 1-√3 and 1+√3 give rise to the quadratic factor ...

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The complex root 7-i has a conjugate that is also a root. These two roots give rise to the quadratic factor ...

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The product of these two quadratic factors is ...

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7 0
3 years ago
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Solve 5x^2 − 3x + 17 = 9.
Vedmedyk [2.9K]

Answer:

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

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b = -3

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therefore,

x = \frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}

or

x = \frac{3\pm\sqrt{9-160}}{10}

or

x = \frac{3+\sqrt{-151}}{10} and x = \frac{3-\sqrt{-151}}{10}

or

x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

here i = √(-1)

Hence,

The roots of the equation are x = \frac{3+\sqrt{151}i}{10} and x = \frac{3-\sqrt{151}i}{10}

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Answer:

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Answer:

5 hours

Step-by-step explanation:

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