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2 years ago

Am in 8 groups. I am larger than 50. I have 7 in each of my groups. What product am i?

Mathematics

1 answer:

Sergio [31]2 years ago

3 0

Answer:

Step-by-step explanation:

8 times 7=56

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What are the LCM of 5 and 7

victus00 [196]

7 ×5 = 35 and 5 × 7 = 35
ans is 35

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3 years ago

I-Ready

MAVERICK [17]

Answer: the answer is -2 1/3

Step-by-step explanation: it would be -2 1/3 because 5 + 2=7 and then add the 1/3 to make -7 1/3

5 0

2 years ago

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A company’s sales decreased 5% this year to $6,585. What were their sales last year?

Feliz [49]

Answer:

$6932

Step-by-step explanation:

Let last year's sales = x. Since there was a decrease of 5%, that means this year's sales are 95% of last year's sales.

So, .95x = 6585

x = 6932 to the nearest dollar

5 0

2 years ago

Runners in a long distance race start out going 6 kilometers east and then head north for the remainder of the race. The finish

Harrizon [31]

Answer:

Step-by-step explanation:

alright lets get started.

Please refer the diagram I have attached.

the runner traveled, six kilometers east.

Next, they turn to north and suppose they run x kilometers.

The starting and the ending points distance is 10 kilometers.

There will be a right triangle formed, we can find the value of x by using Pythagorean theorem.

$a^2+b^2=c^2$

$6^2+x^2=10^2$

$36+x^2=100$

Subtracting 36 from both sides

$x^2=100-36=64$

$x=8$

So, the runners travel 8 kilometers to the north. : answer

Hope it will help. :)

6 0

2 years ago

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If $3,000 is deposited at the end of every six months into an account that earns 10% semiannually, find the amount after 10 year

lesya [120]

Answer:

7959.83

Step-by-step explanation:

A = P ( 1+r/n)^ nt

Where A is the amount in the account

P is the principal

r is the rate

n is the number of compoundings per year

t is the years

A =3000 ( 1+.10/2)^ 2*10

A =3000 ( 1+.05)^ 20

=7959.83

6 0

2 years ago

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