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3 years ago

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The normal shape of an enzyme is as shown in structure A. If the enzyme’s shape changes to that shown in structure B, what are t

wo consequences of this change

1 answer:

Rasek [7]3 years ago

8 0

Answer: More binding of substrate and will follow the lock-and-key pattern of enzyme binding are the Plato answers

Explanation:

just took the test my guy

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PLEASE HELP!! 50 POINTS!!! WILL MARK BRAINLEST!!!!

Volgvan

Answer:

Baking soda mixed with Vinegar

Explanation:

This is a chemical reaction that I have seen in my daily life. Vinegar is acidic while baking soda is a base. The 2 mix together to form carbonic acid and sodium acetate from sodium and bicarbonate ions.

4 0

3 years ago

Read 2 more answers

consider the reaction between calcium oxide and carbon dioxide: cao ( s ) + co 2 ( g ) → caco 3 ( s ) a chemist allows 14.4 g of

MakcuM [25]

Answer:

CaO is the limiting reagent

Theoritical yield = 25.71 g

% Yield = 75.44%

Explanation:

1 mole = Molar mass of the substance

Molar Mass of CaO = 56 g/mol

Molar Mass of CaCO3 = 100 g/mol

Molar mass of CO2 = 44 g/mol

The balanced Equation is :

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO reacts with = 1 mole of CO2

56 g of CaO reacts with = 44 g of CO2

1 g of CaO reacts with =

$\frac{44}{56}$

= 0.785 g of CO2

So,

<u>14.4 g of CaO</u><u> </u>must react with = (14.4 x 0.785) g of CO2

= 11.31 g of CO2

<u>Needed = 11.31 g</u>

<u>Available CO2 = 13.8 g</u><u> </u>(given)

So CO2 is in excess , hence<u> CaO is the limiting reagent and product will produce from 14.4 g of CaO</u>

$CaO + CO_{2}\rightarrow CaCO_{3}$

1 mole of CaO will produce 1 mole pf CaCO3

56 g of CaO produce = 100 g of CaCO3

1 g of CaO produce =

$\frac{100}{56}$

= 1.785 g of CaCO3

14.4 g of CaO will produce = (1.785 x 14.4) g of CaCO3

= 25.71 g of CaCO3

Theoritical Yield of CaCO3 = 25.71 g

Actual yield = 19.4 g

Percent Yield =

$\frac{Actual\ yield}{Theoritical\ yield}\times 100$

$\frac{19.4}{25.71}\times 100$

= 75.44 %

6 0

3 years ago

Step2247 [10]

A) Combustion
Hope this helps

8 0

4 years ago

Read 2 more answers

How many moles of Aluminum are produced when34.2 g of alumina are broken down through the process of electrolysis

Elan Coil [88]

Answer:

0.670 mol

Explanation:

Step 1: Write the balanced reaction for the decomposition of alumina

2 Al₂O₃ ⇒ 4 Al + 3 O₂

Step 2: Calculate the moles corresponding to 34.2 g of Al₂O₃

The molar mass of Al₂O₃ is 101.96 g/mol.

34.2 g × 1 mol/101.96 g = 0.335 mol

Step 3: Calculate the moles of Al produced from 0.335 moles of Al₂O₃

The molar ratio of Al₂O₃ to Al is 2:4.

0.335 mol Al₂O₃ × (4 mol Al/2 mol Al₂O₃) = 0.670 mol Al

6 0

3 years ago

kap26 [50]

Answer:

A they share two covalent bonds

8 0

3 years ago