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geniusboy [140]
3 years ago
8

Number six on the page

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
A square has the same length on all of it's sides. The area of a square is side times side. So it's 2.2×2.2=?
You might be interested in
9) The length of segment AE is 12. Find the coordinate of E.
Mashcka [7]

Answer:

-18

Step-by-step explanation:

A is at -30. AE = 12

So, E is -30+12 = -18

6 0
3 years ago
Trapezoid TRAP was dilated by a scale factor of one half to create trapezoid T'R'A'P'.
alexira [117]

Answer:

Point X

Step-by-step explanation:

If you look, you can see that X is the center point for both TRAP and T'R'A'P'. I also just took the test myself and got it correct.

Hope this helps!

6 0
3 years ago
Read 2 more answers
1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é: a) r = 6 b) r = 7 c) r = 9 d
Maslowich

Answer:

1) b) r = 7

2) e) 82

Step-by-step explanation:

Progressão aritmética:

Em uma progressão aritmética, a diferença entre termos consecutivos é sempre a mesma, chamada de razão.

O n-ésimo termo de uma PA é dado por, tomando o primeiro termo como referência:

a_n = a_1 + (n-1)r

Tomando o m-ésimo termo como referência, tem-se que:

a_n = a_m + (n-m)r

1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é:

a_5 = 40, a_9 = 68. Então:

a_n = a_m + (n-m)r

68 = 40 + 4r

4r = 28

r = \frac{28}{4} = 7

Então a resposta correta é dada pela alternativa b.

2) Inserindo-se 6 números entre 72 e 107, de modo que a sequência (72, a2, a3, a4, a5, a6, a7 ,107) seja uma progressão aritmética, tem-se a3 igual a:

O primeiro termo é a_1 = 72 e o oitavo termo é a_8 = 107. Com isso, é possível encontrar a razão.

a_n = a_1 + (n-1)r

107 = 72 + 7r

7r = 35

r = \frac{35}{7} = 5

Então, o terceiro termo é:

a_3 = a_1 + 2r = 72 + 2(5) = 82

Logo, a resposta correta é dada pela alternativa e.

5 0
3 years ago
Are 3/4 and 12/9 equivalent explain your answer?​
julia-pushkina [17]

yes

12/9=4/3

we used reciprocal here

7 0
4 years ago
Find the midpoint of the line segment whose endoints are 3,10 and 7,8
aliina [53]
The midpoint would be (5,9)
8 0
4 years ago
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