Answer:
- A'(4, -4)
- B'(0, -3)
- C'(2, -1)
- D'(3, -2)
Step-by-step explanation:
The coordinate transformation for a 270° clockwise rotation is the same as for a 90° counterclockwise rotation:
(x, y) ⇒ (-y, x)
The rotated points are ...
A(-4, -4) ⇒ A'(4, -4)
B(-3, 0) ⇒ B'(0, -3)
C(-1, -2) ⇒ C'(2, -1)
D(-2, -3) ⇒ D'(3, -2)
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<em>Additional comment</em>
To derive and/or remember these transformations, it might be useful to consider where a point came from when it ends up on the x- or y-axis.
A point must have come from the -y axis if rotating it 270° CW makes it end up on the +x-axis. A point must have come from the x-axis if rotating it 270° makes it end up on the +y axis. That is why we write ...
(x, y) ⇒ (-y, x) . . . . . . the new x came from -y; the new y came from x
The angles inside a triangle add up to 180°
The 3rd angle is supplementary to (6x+1)°
Supplementary means they make a straight line (i.e 180°)
1st angle = 79°
2nd angle = (2x+10)°
3rd angle = 180° - (6x+1)°
180 = 79 + (2x+10) + 180 - (6x+1)
180 = 79 + 2x + 10 + 180 - 6x - 1
combine like terms
180 - 180 - 79 - 10 + 1 = 2x - 6x
-88 = -4x
-88/-4 = x
22 = x
Answer:
2x+x
Step-by-step explanation:
