Ask question

Ask question

All categories

2 years ago

13

A certain rectangular has a height of 4 length of 3 and width of 7 give the dimensions of second prism that has the same surface

area of the first one the dimensions have to be different

1 answer:

DIA [1.3K]2 years ago

3 0

Im going with rectangle and square

You might be interested in

PLSSS HELP IF YOU TURLY KNOW THISS

Eduardwww [97]

Answer:

Step-by-step explanation:

3² * 5³ = 3*3 * 5*5*5

= 9 * 125

= 1125

8 0

2 years ago

Read 2 more answers

Kayla is going on a trip. The mass of everything she is packing is 8.1 kg. She packs everything into a bag that has a mass when

Agata [3.3K]

Answer:

8.81 KG (8810 g)

Step-by-step explanation:

8.1 KG (8100 g) + 710 g

8 0

2 years ago

Read 2 more answers

What is the constant rate of change in the table?

Zina [86]

Well,you have the answer on your paper already...

8 0

2 years ago

3x+8 •59 solve for x

Marina86 [1]

1) Let's solve for x, writing this equation.

3x +8*59 =0

3x +472=0 <em>Subtract 472 from both sides</em>

3x = -472

x= -472/3 or -157.33

2) So the answer is x= -472/3

6 0

8 months ago

Question 16 (Essay Worth 7 points)<br><br> Verify the identity.<br><br> tan (x + π/2) = -cot x

Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

$\frac{sin(x+pi/2)}{cos(x+pi/2)}$

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

$\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)} = \frac{cos(x)}{cos(x+\pi/2) }$

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

$\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)$

6 0

2 years ago