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3 years ago

6th grade help me Algebra I think

Mathematics

1 answer:

scoundrel [369]3 years ago

6 0

n - 7 = 21, n= 28 should be right bc the difference of 28 and 7 is 21

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In the equation 9^2 x 27^3 = 3^x, what is the value of x? <br> Show your work on scratchpaper

IceJOKER [234]

Answer:

x=13

Step-by-step explanation:

9^2 * 27^3 = 3^x

We need to get each term with a base of 3

9^2 = (3^2) ^2

We know that a^b^c = a^(b*c)

(3^2) ^2 = 3^(2+2) = 3^4

27^3 = (3^3) ^3 = 3^(3*3) = 3^9

Replacing these in the original equation

3^4 * 3^9 = 3^x

We know that a^b *a^c = a^(b+c)

3^4 * 3^9 =3^(4+9) = 3^13 = 3^x

The bases are the same, so the exponents must be the same

x=13

7 0

3 years ago

Please help me I need to solve by factoring!!

Sveta_85 [38]

Answer:

x=5

Step-by-step explanation:

3x^2=15x

Subtract 15x from both sides

3x^2-15x=0

Factor out 3x

3x(x-5)=0

Since 0 divided by any number is zero, we get that:

x-5=0

x=5

8 0

3 years ago

-2/3(3x-9) = 15 please help

Lina20 [59]

Your answer would be x=-10.5

First distribute -2/3 to 3x and -9
-2x+6=15
Then subtract 6 from both sides
-2x=9
Divide both sides by -2
x=-4.5

6 0

3 years ago

Please help ill give brainliest

Naddik [55]

I think it’s option a

8 0

3 years ago

Find the length of EF

Lisa [10]

Answer:

Step-by-step explanation:

1. First, we need to set up an equation to find the value of x and then the length of EF.

2. We know that DG is equal to 33, so we can add all the three sections it's cut into altogether to get 33. Therefore, we get an equation of: $3x - 28 + 3x - 30 + x = 33$

3. (Solving for x)

Step 1: Simplify both sides of the equation.

$3x - 28 + 3x - 30 + x = 33$
$(3x+3x+x) + (-28-30)=33$
$7x - 58 = 33$

Step 2: Add 58 to both sides.

$7x - 58 + 58 = 33 + 58$
$7x = 91$

Step 3: Divide both sides by 7.

$\frac{7x}{7} = \frac{91}{7}$
$x = 13$

4. Now that we know x is equal to 13, we can plug that value in for the expression 3x - 30.

$3(13)-30$
$39 - 30$
$9$

Therefore, the length of EF is 9.

7 0

3 years ago