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3 years ago

Help lol easy

Mathematics

1 answer:

34kurt3 years ago

3 0

Answer:

0.85 DOLLARS

Step-by-step explanation:

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Simplify the following expression. 1/4 (24-16x) a. 6+4x b. 6+4 c. 6-4x d. 6-4

adoni [48]

Answer is 6-4x

1/4 evaluates to 1/4

Multiply x and 16

Multiply x and 1

after you have the answer it should come out to 24-16x then multiply 1/4 * 24-16x

1/4 *24=6

1/4*(24-16*x) evaluates to 6-4x

5 0

3 years ago

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Find the area of the shaded region. pls do this with explanation.

vladimir1956 [14]

Answer:

first find the area of the big rectangle = 12×14=168

area of the small unshaded rectangle =2×5×6=60

area of the shaded region = 168-60=108

6 0

3 years ago

Read 2 more answers

3.Not Answered 4.Not Answered 5.Not Answered 6.Not Answered 7.Not Answered 8.Not Answered 9.Not Answered 10.Not Answered 11.Not

tino4ka555 [31]

Answer:

The answer to your question is Dependent Variable.

In a linear regression model, the variable that is being predicted or explained is known as Dependent Variable . It is denoted by y and is often referred to as the response variable

Step-by-step explanation:

I don't really know how to explain sorry.

Brainliest pls! :)

8 0

3 years ago

Helpppppppppp ASAP pls and thankyouu

natima [27]

Answer:

1. The graph of the inequality, y > -3·x - 2, created with MS Excel is attached showing the following characteristics;

Linear

Shade is above the line

2. The graph of the inequality, y ≤ │x│ - 3, created with MS Excel is attached showing the following characteristics

Linear

Shade is below the line

3. The graph of the inequality, y < x² - 4, created with MS Excel s attached showing the following characteristics;

Quadratic

Shade below the line

Step-by-step explanation:

8 0

3 years ago

Sin(x+pi/4)-sin(x-pi/4)=1 solve the equation

evablogger [386]

Sin(α+β)=sin(α)cos(β)+cos(α)sin(β)
sin(α-β)=sin(α)cos(β)-cos(α)sin(β)

$sin(x+ \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} \\ sin(x- \frac{ \pi }{4} )=sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} \\ \\ \\sin(x+ \frac{ \pi }{4} )-sin(x- \frac{ \pi }{4} ) =1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -(sin(x)cos\frac{ \pi }{4} -cos(x)sin\frac{ \pi }{4} )=1 \\ sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} -sin(x)cos\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\ cos(x)sin\frac{ \pi }{4} +cos(x)sin\frac{ \pi }{4} =1 \\$
$2cos(x)sin\frac{ \pi }{4} =1 \\ sin\frac{ \pi }{4} = \frac{ \sqrt{2} }{2} \\ 2cos(x) \frac{ \sqrt{2} }{2} =1 \\ 2 \cdot \frac{ \sqrt{2} }{2}cos(x) =1 \\ \sqrt{2} cos(x)=1 \\$
$cos(x)= \frac{1}{ \sqrt{2} } \\ x=\pm arccos \frac{1}{ \sqrt{2} }+2 \pi k , k \in Z \\ x=\pm \frac{ \pi }{4} +2 \pi k , k \in Z$

6 0

3 years ago