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kondaur [170]
3 years ago
7

What problem would be created by using classes of 60-120, 120-180,...?

Mathematics
1 answer:
Virty [35]3 years ago
8 0
<h3>Explanation:</h3>

  Class boundaries need to be defined so that a point on the boundary is unambiguously placed in one class or the other. With these boundaries, a value of 120 might be placed in the first or the second class—<em>we don't know which</em>.

_____

It is customary to define class boundaries between data values 60.5–120.5, for example, so that no data value can fall on the boundary, or as a semi-open interval [60, 120), so that a boundary value is clearly placed into a specific class.

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The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
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By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
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