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allochka39001 [22]
3 years ago
13

Solve x3 = 1 over 8. 1 over 2 ±1 over 2 1 over 4 ±1 over 4

Mathematics
1 answer:
cricket20 [7]3 years ago
7 0
X³ =  1/8

Take the cube root of both sides.

∛x³  = ∛(1/8)

Since x³ has 3 of such x multiplying each other so we bring out 1 of the x from the cube root sign as discussed.

x = ∛((1/2)*(1/2)*(1/2))

We bring out 1 of the (1/2) out of the cube root sign as well.

x = 1/2

So the answer is the first option.  1 over 2.

I hope this helps.
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WILL GIVE BRAINLIEST! SUPER CONFUSED!!!
kondor19780726 [428]

Answer:

For 1948 Men's :Interquartile range is 1.5, Median is 58.3

For 2012 Men's: Interquartile range is 0.315, Median is 47.86

You can infer that in 2012 the swimmers were better and it was more competitive as the interquartile range was lower and the median was also lower as well

Step-by-step explanation:

1948 Men's 100m

57.3, 57.8, 58.1, 58.3, 58.3, 59.3, 59.6,1:00.5

               ⬆                ⬆                 ⬆

         Low IQR      Median       High IQR

Low IQR is average of 57.8 and 58.1 = 57.95

High IQR  is average of 59.3 and 59.6 =  59.45

Median is average of 58.3 and 58.3 = 58.3

Interquartile range is High IQR- Low IQR

59.45 - 57.95=1.5

2012 Men's 100m

47.52, 47.53, 47.8, 47.84, 47.88, 47.92, 48.04, 48.44

                    ⬆                  ⬆                      ⬆

             Low IQR         Median          High IQR

Low IQR is average of 47.53 and 47.8 = 47.665

High IQR is average of 48.04 and 47.92 = 47.98

Median is average of 47.88 and 47.84 = 47.86

Interquartile range is High IQR-Low IQR

47.98-47.665=0.315

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3 years ago
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Factor the following:
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3 years ago
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Answer:

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3 years ago
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Step-by-step explanation:

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