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3 years ago

I need help with this worksheet please help

Mathematics

1 answer:

navik [9.2K]3 years ago

6 0

Remember to use y=mx+b there telling u for top left solve for that n grapgh y is mx up n down b is x left n right

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Solve for x<br> 8x+4=6x-10<br> x=?

mamaluj [8]

8x+4 = 6x-10

To solve for x you'll want to move all the terms containing x onto the left side of the equation and all the other terms on the right side of the equation.

1. Subtract 6x from both sides.

2x+4 = -10

2. Subtract 4 from both sides.

2x = -14

3. Divide both sides by 2.

x = -7

Answer is:

-7

7 0

3 years ago

Read 2 more answers

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

4 years ago

What is the value of y

Flura [38]

It can be anything. If you are talking about math

6 0

4 years ago

How to simplify numbers

Leto [7]

Hopes this helps:

Answer:

•ROUND IT OFF
Create zeros.
So 199 becomes 200.

•ROUND THE ORDER OF MAGNITUDE
Round a lot, to the nearest “power ten”.
So 218 comes 100, and 2,180 becomes 1,000.

•SLIDE THE DECIMAL POINT
Compact those zeros created by rounding.
So 200,000,000 becomes 2•10^8 (exponential notation).

•SUBSTITUTE A NUMBER YOU CAN REMEMBER
Instead of rounding, find a nearby number you can remember.
So 218 becomes 222, or 210 or 200, something else easy.

8 0

3 years ago

Read 2 more answers

Ajar contains 30 red, 40 blue, and 50

nikitadnepr [17]

1/30
because 30+40+50=120
40/120= 1/30

8 0

3 years ago