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slamgirl [31]
1 year ago
7

Ху Evaluate when x = 6 and y = 13. x + y

Mathematics
1 answer:
storchak [24]1 year ago
7 0

EXPLANATION

When x=6 and y=13 x+y = 6 + 13 = 19

x + y = 19

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Help me please !!!!!!!!!​
Svetllana [295]

Answer:

x=6   y=9

Step-by-step explanation:

Im sorry if it didn't help! But goodluck!!!!

4 0
3 years ago
-8-8(6n+1) solve using distributive property
cupoosta [38]

Answer:

-48n-16

Step-by-step explanation:

-8 -8(6n +1)

= -8 + -48n + -8

= (-48n) + (-8 + -8)

= -48n + -16

8 0
3 years ago
out of a swarm of bees one fifth part settled on a kadamba blossom; one third on a silihindra flower; three times the difference
Lisa [10]
setting things up:<em>
let x be the # of bees in the swarm, then </em>
\frac{x}{5}+\frac{x}{3}+3(\frac{x}{3}-\frac{x}{5})+1=x

<span><em>multiply across by 15</em>
</span>3x+5x+3(5x-3x)+15=15x
8x+3(2x)+15=15x
8x+6x+15=15x
14x+15=15x
15=x\leftrightarrow x=15
5 0
3 years ago
If this figure is dilated by a scale factor of 3, what would the new coordinates be?
QveST [7]

Answer:

J (-3,3), G (0,3), H (4,9), I (3,3)

Step-by-step explanation:

When your dilating a figuring it either gets larger or smaller. Since this is a positive number, and it is not a fraction then the figure is getting larger. Now you multiply each of the original coordinates by 3 to get the dilated coordinates.

(For learning purposes only)

8 0
3 years ago
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following p
igor_vitrenko [27]

The required probability of success is given by 0.98906500

Assume the random variable X has a binomial distribution with the given probability of obtaining a success.
P(X<5), n=6, p=0.3

<h3>What is binomial distribution?</h3>

In binomial distribution for number trials we are investigating the probability of getting a success remain the same.


n = number of trails,
p = probability of success
x = the number of success

p(x<5) = P(x=0)+ p(x=1) + p(x=2)+p(x=3)+p(x=4)

= \binom{6}{0}(0.3)^0(1-0.3)^6+\binom{6}{1}(0.3)^1(1-0.3)^5+\binom{6}{2}(0.3)^2(1-0.3)^4+\binom{6}{3}(0.3)^3(1-0.3)^3+\binom{6}{4}(0.3)^4(1-0.3)^2

p(x<5) = 0.98906500

Thus the required  probability of success is given by 0.98906500

Learn more about Binomial distribution here:
brainly.com/question/14565246

#SPJ1



3 0
3 years ago
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