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hodyreva [135]
3 years ago
10

22.700 nearest hundredth/6413202/1c463fd9?utm_source=registration

Mathematics
1 answer:
Vesnalui [34]3 years ago
4 0
You already have the answer in the question
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20x 10 <= (less then or equal to) 90
Mamont248 [21]

Answer:

x(less than or equal to)5

Step-by-step explanation:

add 10 to both sides

20x-10(less than or equal to) 90

       +10                                  +10

20x (less than or equal to) 100

divide by 20 to isolate the variable

20x(less than or equal to) 100

/20                                       /20

x (less than or equal to) 5

5 0
3 years ago
Which statement comparing 6² + 14 ÷ 2 and 100−82 is true?
Elanso [62]

Answer:

A)62+14÷2>100−82

Step-by-step explanation:

6² + 14 ÷ 2 =36+7=43

100−82=18

so,

43>18

62+14÷2>100−82

8 0
3 years ago
Read 2 more answers
Polly has 6 cookies Kate takes away 4 how many cookies does Polly have left
Tatiana [17]
2 because 6 minus 4 is 2

4 0
3 years ago
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The cable company takes an simple random sample of 250 of the approximately 15,000 households who subscribe to them. They found
finlep [7]

Answer:

The standard deviation of the sampling distribution of p is 0.03.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\mu_{\hat p}=p  

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

It is provided that, a cable company takes an simple random sample of 250 of the approximately 15,000 households who subscribe to them to determine the proportion of households that watch sports on television at least once a month.

The actual proportion is 70%.

As the sample selected is quite large, i.e. <em>n</em> = 250 > 30, the central limit theorem can be used to approximate the sampling distribution of sample proportions.

Compute the standard deviation of this sampling distribution as follows:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

=\sqrt{\frac{0.70(1-0.70)}{250}}\\\\=0.0289828\\\\\approx 0.03

Thus, the standard deviation of the sampling distribution of p is 0.03.

5 0
4 years ago
I’m bored but and I really don’t wanna do this
Sindrei [870]

Answer: its A

Also I can understand why you don't want to do it. lol

8 0
3 years ago
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