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3 years ago

Can an equilateral triangle ever be a right triangle too?

2 answers:

7 0

No, it never can be a right triangle.

First, all the angles of an equilateral triangle is 60 degrees because all angles are the same and all the angles add up to 180:

180/3 = 60.

So if it is a right angle it needs one angle 90 degrees which an equilateral triangle can't have,

Soloha48 [4]3 years ago

4 0

No, because a equilateral triangle has all even sides and a right triangle has no equal sides. There for a equilateral triangle can not be equal to a right triangle.

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What is slope-intercept form of a line that passes through points (2,11) and (4,17)?

kramer

Answer:

y = 3x + 5

Step-by-step explanation:

Okay, so first we do the equation for rise over run which is y2 - y1/ x2 - x1

so plug the numbers 11 - 17/ 4 - 2 getting the slope -3, now since we found the slope we need to find the intercept form, what you have to do now is plug in a coordinate from the x value and y value one of the pairs essentially so,

y = 3x + b, I chose your first pair

11 = 3 x 2 + b

equals to,

11 = 6 + b

now we want b, by itself.

5 = b

so the total intercept form answer is

y = 3x + 5

I will check over it,

11 = 3 x 2 + 5

11 = 11

I hope this helped!

6 0

3 years ago

A bank offers an interest rate of 4% on a savings account . Write 4% as a decimal.

Gekata [30.6K]

0.04

Hope this helps & good luck. :)

5 0

3 years ago

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Anybody wanna c h at zoo m<br> 928-1137-7133<br> HtHq72

docker41 [41]

Nahh
Explanation: noooo

5 0

3 years ago

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Plz answer asap!!!!!!!!!!!!!!!!!!!!!!

user100 [1]

Answer:

It can be represented by the expression 2r, or “two times the radius.” So if you know a circle's radius, you can multiply it by 2 to find the diameter; this also means that if you know a circle's diameter, you can divide by 2 to find the radius. Find the diameter of the circle.

Step-by-step explanation:

you'r welcome :)

6 0

2 years ago

Just Need A Few Questions Answered To Finish My Quiz, Any Help Would Be Much Appreciated.

kvv77 [185]

Given the triangle

PQR

with points

P(8,0)

Q(6,2)

R(-2,-4)

And the triangle

P'Q'R'

with points

P'(4,0)

Q'(3,1)

R'(-1,-2)

Part A. Scale factor

Using the vertex

P( 8, 0)

P'(4,0)

the dilatation factor is given by

$\frac{4}{8}=\frac{1}{2}$

The triangle has a dilatation factor of 1/2

Part B:

P''Q''R'' after using P'Q'R' reflected about the y axis

to make a reflection over the y axis

coordinates (x,y) turn into coordinates (-x,y)

as follows

$P^{\prime}(4,0)\rightarrow P^{\prime\prime}(-4,0)$ $Q^{\prime}(3,1)\rightarrow Q^{\prime\prime}(-3,1)$ $R^{\prime}(-1,-2)\rightarrow R^{\prime\prime}(1,-2)$

Then triangle P''Q''R'' has coordinates

P''(-4,0)

Q''(-3,1)

R''(1,-2)

Part C:

PQR is congruent to P''Q''R''?

Congruent triangles are triangles that have the same size and shape. This means that the corresponding sides are equal and the corresponding angles are equal.

Then the triangles are not congruent

8 0

11 months ago