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aniked [119]
3 years ago
7

Steven ran for class president against Mandy. Steven Recieved 5 votes for every 3 votes that Mandy Recieved. Mandy Recieved 420

votes if all students voted only once how many students voted in the election
Mathematics
1 answer:
ki77a [65]3 years ago
7 0

Answer:

700

Step-by-step explanation:

420×5=2100

2100÷3=700

Answer: 700

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James has a certain amount of money. If he buys $3$ pens and $2$ pencils, he will have $\$2$ left over. If he buys $2$ pens and
labwork [276]

The cost of pen and pencils are related to the number that can be bought

with a given amount of money.

  • <u />\underline{The \ ordered  \ pair \  (a,  \, b)  \ is  \ (6, \,  2)}<u />

Reasons:

The given parameters are;

If  the number number of pens and pencils James buys = 3 pens and 2 pencils, the amount James will have left = $2

If the number of pens and pencils James buys = 2 pens and 3 pencils, the amount James will have left = $6

The amount of money Judith has = The amount of money with James

The number of pens and pencil James and Judith can buy = 6 pens and 6 pencils

The cost of one pen = a

The cost of one pencil = b

Required:

To find the ordered pair (a, b)

Solution:

Let <em>X</em> represent the initial amount of money James has, we get;

X - (3·a + 2·b) = 2...(1)

X - (2·a + 3·b) = 6...(2)

2·X = 6·a + 6·b...(3)

Therefore;

X = (6·a + 6·b) ÷ 2 = 3·a + 3·b

Which from equation (1) gives;

3·a + 3·b - (3·a + 2·b) = 2

3·a + 3·b - 3·a - 2·b = 2

3·b - 2·b = 2

b = 2

Subtracting equation (1) from equation (2) gives;

(X - (2·a + 3·b)) - (X - (3·a + 2·b)) = 6 - 2 = 4

-2·a - 3·b + 3·a + 2·b = 4

a - b = 4

a = 4 + b

∴ a = 4 + 2 = 6

a = 6

<u />

<u />

\underline{The \ ordered  \ pair \  (a,  \, b)  \ is  \ (6, \,  2)}<u />

Learn more about word problems and simultaneous equations here:

brainly.com/question/14294864

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\displaystyle |\Omega|=\binom{14}{6}=\dfrac{14!}{6!8!}=\dfrac{9\cdot10\cdot11\cdot12\cdot13 \cdot14}{2\cdot3\cdot4\cdot5\cdot6}=3003\\ |A'|=\binom{11}{3}=\dfrac{11!}{3!8!}=\dfrac{9\cdot10\cdot11}{2\cdot3}=165\\ |A|=3003-165=2838\\\\ P(A)=\dfrac{2838}{3003}=\dfrac{86}{91}\approx95\%

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