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aksik [14]
3 years ago
14

a) The radius of a circular field is 42 m. Find the perimeter of the field. Also find the length of wire required to fence it wi

th 5 rounds ​
Mathematics
2 answers:
rewona [7]3 years ago
5 0

263.89

263.89*5=1319.45

pishuonlain [190]3 years ago
5 0

We are given with the radius of the circular field,

r = 42 \: m

And, we have to find the perimeter of the field. Also, we have to find the length of the wire required to fence it with 5 rounds:

<u>We know,</u>

Perimeter of a circle = 2πr, where r is the radius of the circle, So let's find the perimeter by using this formula.

perimeter = 2\pi r

perimeter = 2 \times  \dfrac{22}{7}  \times  \: 42 m

perimeter = 2 \times 22 \times 6 \: m

perimeter =  \boxed{264  \: m}

Now, finding the length of the wire which is equals to 5 × Perimeter of the circular field.

length \: of \: wire = 264 \: m  \times 5

length \: of \: wire =  \boxed{1320 \: m}

And we are done !!

#CarryOnLearning.

<u>━━━━━━━━━━━━━━━━━━━━</u>

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A report on consumer financial literacy summarized data from a representative sample of 1,663 adult Americans. Based on data fro
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a) 95% Confidence interval = (0.536, 0.584)

This means that we are 95% confident that between 53.6% and 58.4% of Americans would give themselves grade of A or B on their financial knowledge of personal finance.

b) The result of the 95% confidence interval agrees with the claim that majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance because the interval obtained for possible values that the population proportion of Americans that would give themselves a grade of A or B on their financial knowledge of personal finance lies completely on the side that is greater than a proportion of 0.50 which indicates that truly, majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance.

Step-by-step explanation:

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Confidence Interval = (Sample proportion) ± (Margin of error)

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Margin of Error is the width of the confidence interval about the mean.

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Margin of Error = (Critical value) × (standard Error)

Critical value at 95% confidence interval for sample size of 1663 is obtained from the z-tables as the sample size is large enough for the sample properties to approximate the population properties.

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Standard error of the mean = σₓ = √[p(1-p)/n]

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95% Confidence Interval = (Sample proportion) ± [(Critical value) × (standard Error)]

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b) The result of the 95% confidence interval agrees with the claim that majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance because the interval obtained for possible values that the population proportion of Americans that would give themselves a grade of A or B on their financial knowledge of personal finance lies completely on the side that is greater than a proportion of 0.50 which indicates that truly, majority of Americans would give themselves a grade of A or B on their financial knowledge of personal finance.

Hope this Helps!!!

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