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Law Incorporation [45]

3 years ago

8

a subsription is $4.95 per month and 4-by-6 inch prints are $0.18 each.How many prints does .insert person here lol. purchase if

the charge for january is $11.43. helpppppppp

2 answers:

sweet [91]3 years ago

6 0

I think the answer is 36 prints

valentinak56 [21]3 years ago

5 0

The number of prints he buys is 36

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Juan and Nina are in the Junior High Orchestra. As part of the orchestra they each have to learn two instruments. Juan is learni

larisa86 [58]

Answer:

Nina practiced the viola for 11.25 hours last week.

Step-by-step explanation:

Juan practiced the violin for 9 hours last week. For each 3 hours that he practices the violin, he practices 2.5 hours of cello. So

3h violin - 2.5h cello

9h violin - xh cello

$3x = 9*2.5$

$x = 7.5$

He practiced 7.5 hours of cello, the same as Nina.

For every 3 hours Nina spends practicing the viola she practices the cello for 2 hours. So:

3h viola - 2h cello

xh viola - 7.5h cello

$2x = 3*7.5$

$x = 7.5*1.5$

$x = 11.25$

Nina practiced the viola for 11.25 hours last week.

7 0

3 years ago

The value of 8 in 56982 is how many times larger than the value of 8 in 156408

Len [333]

The value of 8 in '56982' is 80 whereas the value of 8 in '156408' is just 8 so the value of the 8 in 56982 is x10 larger than the value of 8 in 156408.
Hope this helps x

3 0

3 years ago

Read 2 more answers

Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

3 years ago

The graph of a proportional relationship passes through (9, 18) and (1, y). Find y.

spayn [35]

Answer:

2

Step-by-step explanation:

Because it's a proportional relationship and it goes through the point (9, 18) the equation is y = 2x so when x = 1, y = 2.

8 0

3 years ago

Please help, and get explanation but please make sure your correct tysm!

Darya [45]

The answer is 12,825 kg because if one car equals 1425 kg and a car carrier can hold 9 cars, then you just have to multiply 1425 by 9 to get 12,825

4 0

3 years ago

Read 2 more answers