Question

What are the zeros of y=x^2 +2x -8

Answer 1

Answer:

x = 2 and ( -4)

Step-by-step explanation:

We have to find the zero factors of the given equation

y = x² + 2x - 8

for zero factor we will put y = 0

0 = x² + 2x - 8

0 = x² + 4x - 2x - 8

0 = x (x+4) - 2(x + 4)

0 = (x + 4) (x - 2)

So zero factors will be

x + 4 = 0

x = -4

( x-2) = 0

x = 2

Therefore, x = 2 and ( -4) will be the zeros of the given equation.

Answer 2

Y = x² + 2x - 8

which two numbers add up to 2 and multiply to -8?

-2 and 4

so rewrite the expression using the above;

(x - 2)(x + 4)
x = 2, -4

so the zeros are 2 and -4.

hope this helps, God bless!